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Zepler [3.9K]
3 years ago
6

How do models help scientists predict the polarity of molecules?

Chemistry
2 answers:
yuradex [85]3 years ago
8 0

Answer:There are three main properties of chemical bonds that must be considered—namely, their strength, length, and polarity. The polarity of a bond is the distribution of electrical charge over the atoms joined by the bond. Specifically, it is found that, while bonds between identical atoms (as in H2) are electrically uniform in the sense that both hydrogen atoms are electrically neutral, bonds between atoms of different elements are electrically inequivalent. In hydrogen chloride, for example, the hydrogen atom is slightly positively charged whereas the chlorine atom is slightly negatively charged. The slight electrical charges on dissimilar atoms are called partial charges, and the presence of partial charges signifies the occurrence of a polar bond.

Explanation:

Svetach [21]3 years ago
7 0

Answer:

The first activity was developed in collaboration with our student teacher, Dr. Chris Sosa. In this activity, the students model the pull of electrons in a bond between two elements, demonstrating covalent bonding. In particular, they practice differentiating between polar and nonpolar bonds. Most compounds, however, have polar covalent bonds, which means that electrons are shared unequally between the bonded atoms. Figure 9.3.1

9.3.

1

compares the electron distribution in a polar covalent bond with those in an ideally covalent and an ideally ionic bond. Recall that a lowercase Greek delta (δ

δ

) is used to indicate that a bonded atom possesses a partial positive charge, indicated by δ+

δ

+

, or a partial negative charge, indicated by δ−

δ

−

, and a bond between two atoms that possess partial charges is a polar bond.

Read more on Brainly.com - brainly.com/question/13921838#readmore

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Given that the freezing point depression constant for water is 1.86°c kg/mol, calculate the change in freezing point for a 0.907
melamori03 [73]

Answer : The correct answer for change in freezing point = 1.69 ° C

Freezing point depression :

It is defined as depression in freezing point of solvent when volatile or non volatile solute is added .

SO when any solute is added freezing point of solution is less than freezing point of pure solvent . This depression in freezing point is directly proportional to molal concentration of solute .

It can be expressed as :

ΔTf = Freezing point of pure solvent - freezing point of solution = i* kf * m

Where : ΔTf = change in freezing point (°C)

i = Von't Hoff factor

kf =molal freezing point depression constant of solvent.\frac{^0 C}{m}

m = molality of solute (m or \frac{mol}{Kg} )

Given : kf = 1.86 \frac{^0 C*Kg}{mol}

m = 0.907 \frac{mol}{Kg} )

Von't Hoff factor for non volatile solute is always = 1 .Since the sugar is non volatile solute , so i = 1

Plugging value in expression :

ΔTf = 1* 1.86 \frac{^0 C*Kg}{mol} * 0.907\frac{mol}{Kg} )

ΔTf = 1.69 ° C

Hence change in freezing point = 1.69 °C

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Jacob floated a long steel sewing needle on a small piece of cork in a glass of water. He noticed that as he turned the glass ar
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3.
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Answer:

2 half-lives=0.8

6 half-lives= 0.05

Explanation

Half-lives are constant and always decrease by half, implying that the concentration decreases by half at a consistent rate.

3.2/2= 1.6/2= 0.8 is two half-lives

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2 years ago
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