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Zepler [3.9K]
3 years ago
6

How do models help scientists predict the polarity of molecules?

Chemistry
2 answers:
yuradex [85]3 years ago
8 0

Answer:There are three main properties of chemical bonds that must be considered—namely, their strength, length, and polarity. The polarity of a bond is the distribution of electrical charge over the atoms joined by the bond. Specifically, it is found that, while bonds between identical atoms (as in H2) are electrically uniform in the sense that both hydrogen atoms are electrically neutral, bonds between atoms of different elements are electrically inequivalent. In hydrogen chloride, for example, the hydrogen atom is slightly positively charged whereas the chlorine atom is slightly negatively charged. The slight electrical charges on dissimilar atoms are called partial charges, and the presence of partial charges signifies the occurrence of a polar bond.

Explanation:

Svetach [21]3 years ago
7 0

Answer:

The first activity was developed in collaboration with our student teacher, Dr. Chris Sosa. In this activity, the students model the pull of electrons in a bond between two elements, demonstrating covalent bonding. In particular, they practice differentiating between polar and nonpolar bonds. Most compounds, however, have polar covalent bonds, which means that electrons are shared unequally between the bonded atoms. Figure 9.3.1

9.3.

1

compares the electron distribution in a polar covalent bond with those in an ideally covalent and an ideally ionic bond. Recall that a lowercase Greek delta (δ

δ

) is used to indicate that a bonded atom possesses a partial positive charge, indicated by δ+

δ

+

, or a partial negative charge, indicated by δ−

δ

−

, and a bond between two atoms that possess partial charges is a polar bond.

Read more on Brainly.com - brainly.com/question/13921838#readmore

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Name the compound formed when a copper cation that has a 2+ charge combines with a bromine anion that has a 1- charge.
Lynna [10]
The compound that is formed when a copper cation and a bromine anion reacts would be Copper (II) bromide. It will have a chemical formula CuBr2. This reaction is a synthesis reaction where two substances reacts to form one product.
6 0
3 years ago
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Why do solids maintain a specific shape and volume?
s344n2d4d5 [400]

Answer:

Solids can hold their shape because their molecules are tightly packed together. ... Atoms and molecules in liquids and gases are bouncing and floating around, free to move where they want. The molecules in a solid are stuck in a specific structure or arrangement of atoms.

<em>Hope it helps...</em>

5 0
3 years ago
What is the volume of an alka seltzer tablet
Delicious77 [7]

Answer:

Explanation:

Alka Seltzer tablet contains 325 mg of aspirin (acetylsalicylic acid), 1000 mg of citric acid, and 1916 mg of sodium bicarbonate. The acids originally contained in a tablet give only 17.4 mmol of H+, which is not enough to neutralize all of the sodium bicar- bonate (22.8 mmol).

3 0
3 years ago
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The solubility of o2 at 20c is 1.38 x10^-3. the partial presure of o2 in the air at sea level is 0.27 atm. using henery;s law, c
netineya [11]

<u>Answer:</u> The solubility of oxygen at 682 torr is 4.58\times 10^{-3}M

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{A}=K_H\times p_{A}

Or,

\frac{C_{1}}{C_{2}}=\frac{p_{1}}{p_2}

where,

C_1\text{ and }p_1 are the initial concentration and partial pressure of oxygen gas

C_2\text{ and }p_2 are the final concentration and partial pressure of oxygen gas

We are given:

Conversion factor used:  1 atm = 760 torr

C_1=1.38\times 10^{-3}M\\p_1=0.27atm\\C_2=?\\p_2=682torr=0.897atm

Putting values in above equation, we get:

\frac{1.38\times 10^{-3}}{C_2}=\frac{0.27atm}{0.897atm}\\\\C_2=\frac{1.38\times 10^{-3}\times 0.897atm}{0.27atm}=4.58\times 10^{-3}M

Hence, the solubility of oxygen gas at 628 torr is 4.58\times 10^{-3}M

4 0
2 years ago
Iodine-131 decays with a half-life of 8.02
dlinn [17]
Radioactive material undergoes 1st order decay kinetics.

For 1st order decay, half life = 0.693/k

where k = rate constant

k = 0.693/half life = 0.693/8.02 = 0.0864 day-1

Now, for 1st order reaction,
k = \frac{2.303}{t} X log \frac{initial.conc}{final.conc}

Given: t = 6.01d, initial conc. = 5mg

∴0.0864 = \frac{2.303}{6.01} X log \frac{5}{final.conc}
∴ final conc. = 2.975 mg
3 0
3 years ago
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