4 cos² x - 3 = 0
4 cos² x = 3
cos² x = 3/4
cos x = ±(√3)/2
Fixing the squared cosine doesn't discriminate among quadrants. There's one in every quadrant
cos x = ± cos(π/6)
Let's do plus first. In general, cos x = cos a has solutions x = ±a + 2πk integer k
cos x = cos(π/6)
x = ±π/6 + 2πk
Minus next.
cos x = -cos(π/6)
cos x = cos(π - π/6)
cos x = cos(5π/6)
x = ±5π/6 + 2πk
We'll write all our solutions as
x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k
Step-by-step explanation:
Given the information:
- 1st square: 12 square units
- 2nd square: DOUBLE that of the first square = 2*12 = 24 square units
From that, we can determine the length of the side in each square:
1/ 
<=> x = 2
2/ 
<=> a = 2
Please have a look at the attached photo.
Hope it will find you well.
Answer:
Function A has a rate of change of 5 and Function B has a rate of change of 4.5. Thus, Function A has a higher rate of change
Step-by-step explanation:
The Solution.
Representing the problem in a diagram, we have
By formula,

In this case,

Substituting these values in the formula above, we get

Clearing the bracket, we get



Dividing both sides by 2, we get

Therefore, the correct answer is option C.