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gregori [183]
3 years ago
8

Problemas de proporcion calidad inversa

Mathematics
1 answer:
Nata [24]3 years ago
3 0

Answer:

A)the answer is 21

B)the answer is 22 days

C)the answer is 71 hours

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Oksi-84 [34.3K]
B is your answer! let me know if you need help!
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3 years ago
Montraie has a coin collection. He keeps 10 of the coins in his box, which is 20% of the collection. How many total coins are in
jek_recluse [69]

By definition of percentages, we conclude that Montraie has 10 coins saved in his box that come from a collection with a total of 50 coins.

<h3>How to calculate the quantity of coins in a collection</h3>

In this question we know the quantity of coins in a box and such coins are part of the <em>coin</em> collection. By definition of percentage we have the <em>total</em> quantity of coins in the collection:

x = 10*(100/20)

x = 50

By definition of percentages, we conclude that Montraie has 10 coins saved in his box that come from a collection with a total of 50 coins.

To learn more on percentages: brainly.com/question/13450942

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4 0
2 years ago
A triangular-shaped window has a base of 3 feet and a height of 4 feet. What is the area of the window?
Simora [160]

Answer:

12 feet

Step-by-step explanation:

4 times 3 is 12 and that is how u find area I think

6 0
2 years ago
Laura spent 78.5% of her paycheck on her mortgage payment. If her paycheck was $1562 how much was her mortgage?
torisob [31]

Answer:

$337.12

Step-by-step explanation:

Multiply $1562 by 78.5% (or 0.785) =1230.88

Then subtract the percent of her paycheck spent (1230.88) from the total of her paycheck(1562) to find out how much is missing(the mortgage payment)

1562-1230.88=337.12

5 0
3 years ago
A professor has learned that three students in his class of 20 will cheat on the final exam. He decides to focus his attention o
balu736 [363]

Answer:

a

P(X \ge 1) = 0.509

b

P(X  \ge 1) = 0.6807

Step-by-step explanation:

From the question we are told that

   The number of students in the class is  N  =  20  (This is the population )

   The number of student that will cheat is  k =  3

   The number of students that he is focused on is  n  =  4

Generally the probability distribution that defines this question is the  Hyper geometrically distributed because four students are focused on without replacing them in the class (i.e in the generally population) and population contains exactly three student that will cheat.

Generally  probability mass function is mathematically represented as

      P(X = x) =  \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}

Here C stands for combination , hence we will be making use of the combination functionality in our calculators  

Generally the that  he finds at least one of the students cheating when he focus his attention on four randomly chosen students during the exam is mathematically represented as

      P(X \ge 1) =  1 - P(X \le 0)

Here  

   P(X \le 0) =  \frac{ ^{3} C_0 *  ^{20 - 3} C_{4- 0}}{ ^{20}C_4}

   P(X \le 0) =  \frac{ ^{3} C_0 *  ^{17} C_{4}}{ ^{20}C_4}

   P(X \le 0) =  \frac{ 1 *  2380}{ 4845}

    P(X \le 0) =  0.491

Hence

    P(X \ge 1) =  1 - 0.491

     P(X \ge 1) = 0.509

Generally the that  he finds at least one of the students cheating when he focus his attention on six randomly chosen students during the exam is mathematically represented as

    P(X \ge 1) =  1 - P(X \le 0)

   P(X  \ge 1) =1- [  \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}]

Here n =  6

So

    P(X  \ge 1) =1- [  \frac{^{3}C_0 * ^{20 -3}C_{6-0}}{^{20}C_6}]

    P(X  \ge 1) =1- [  \frac{^{3}C_0 * ^{17}C_{6}}{^{20}C_6}]

    P(X  \ge 1) =1- [  \frac{1  *  12376}{38760}]

    P(X  \ge 1) =1- 0.3193

    P(X  \ge 1) = 0.6807

   

5 0
3 years ago
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