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horrorfan [7]
3 years ago
10

Hey can somebody help me? I know it seems easy but I forgot the process on how to do this. Thanks in advance!

Mathematics
1 answer:
joja [24]3 years ago
7 0
The answer is 1, because you have got lets say 1 1/2 chocolate (it means one and a half) then if you eat the 1/2 (the half) then you have got 1 chocolate left.
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Please help me answer this
ohaa [14]

i did the awnser is 173,668.18 there you goStep-by-step explanation:

6 0
2 years ago
What is the answer !​
kondor19780726 [428]

Answer:

m∠OKG = 95°

Step-by-step explanation:

In the given question,

Angle OKL and angle OKG are the linear pairs.

And we know that sum of linear pair of angles is 180°.

Therefore, m∠OKL + m∠OKH = 180°

85° + m∠OKH = 180°

m∠OKH = 180° - 85°

              = 95°

Therefore, measure of angle OKG = 95° will be the answer.

3 0
3 years ago
One number is three less than a second number. Six times the first is 6 more than 3 times the second. Find the numbers.
Karolina [17]

Step-by-step explanation:

Given,

x = y - 3

Also,

6(y - 3) = 3y + 6

6y - 18 = 3y + 6

6y - 3y = 6 + 18

3y = 24

y = 24/3

y = 8

x = 8 - 3

x = 5

Therefore, the first number is 5 and the second number is 8.

4 0
3 years ago
100 POINTS!!!! Please be quick and make sure you have a correct answer, no plagiarizing, and no silly answers. Will give BRAINLI
NikAS [45]

Part A

5x 3y^3 2z

I know it is in standard form because there are no more like terms.

Part B: Polynomials are always closed under multiplication. Unlike with addition and subtraction, both the coefficients and exponents can change. The variables and coefficients will automatically fit in a polynomial. When there are exponents in a multiplication problem, they are added, so they will also fit in a polynomial.

6 0
3 years ago
Read 2 more answers
Hello! Can someone please help me with this question ? I’ll mark brainly thanks ! :)
NikAS [45]

Answer:

\Large\boxed{\text{Perpendicular Equation:} \ y = -\frac{2}{7}x + \frac{22}{7}}

\Large\boxed{\text{Parallel Equation:} \ y = \frac{7}{2}x -12}

Step-by-step explanation:

In order to find the equations that are parallel/perpendicular to the line y = \frac{7}{2}x - 4, we need to note a couple things about the relationships between lines and their parallel/perpendicular lines.

  • A) If a line is perpendicular to another, the slopes will be opposite reciprocals (for instance -2 and \frac{1}{2} - multiplied, they equal -1.)
  • B) If a line is parallel to another, they will have the exact same slope.

<h2>Perpendicular:</h2>

We know that the slope of a perpendicular line will be the the opposite reciprocal of the line we're comparing it to.

Since the slope of our base line is \frac{7}{2}, we can find the reciprocal, then the opposite of that.

  • Reciprocal of \frac{7}{2} = \frac{2}{7}
  • Opposite of \frac{2}{7} = -\frac{2}{7}

So the slope of this line will be -\frac{2}{7}, making our equation y = -\frac{2}{7}x+ b

However, y-intercepts will not stay the same. In order to find this, we can substitute the point (4, 2) into our equation to solve for b.

  • 2 = -\frac{2}{7} \cdot 4 + b
  • 2 = -\frac{8}{7} + b
  • b = 2+\frac{8}{7}
  • b = 2 \frac{8}{7}
  • b=\frac{22}{7}

Now we know the y-intercept of this equation is \frac{22}{7}. We can now finish off our equation of the line by substituting that in to what we already have,  y = -\frac{2}{7}x+ b.

y = -\frac{2}{7}x+ \frac{22}{7}

<h2>Parallel:</h2>

As mentioned earlier, parallel lines will have the exact same slope but not the same y-intercept. Since the slope of our original equation is \frac{7}{2}, the slope for this one will also be \frac{7}{2}.

So we now know the equation looks something like y = \frac{7}{2}x + b.

In order to solve for b, we apply the same logic we did in the perpendicular line and substitute in the point (4, 2) into the equation.

  • 2 = \frac{7}{2} \cdot 4 + b
  • 2 = \frac{28}{2}+b
  • 2 = 14+b
  • b = 2-14
  • b =-12

Now that we know the slope and the y-intercept, we can finish off our equation as y = \frac{7}{2}x -12.

Hope this helped!

3 0
3 years ago
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