Answer:
2.267
Step-by-step explanation:
Step 1 of 3: Add.
Add
Highlighted:14 over 15
14
15
Highlighted:+ Highlighted:8 over 15
8
15
+ 4 over 5
4
5
= Highlighted:22 over 15
22
15
+ 4 over 5
4
5
Step 1 of 3: Add, sub-step a: Add.
Add
14 over 15
14
15
+ 8 over 15
8
15
= ( 14 + 8 ) over 15
14 + 8
15
= 22 over 15
22
15
Step 1 of 3: Add.Hide
Step 2 of 3: Add.
Add
22 over 15
22
15
+ 4 over 5
4
5
= 34 over 15
34
15
Step 2 of 3: Add, sub-step a: Find common denominator.
Find common denominator
22 over 15
22
15
+ 4 over 5
4
5
= ( 22 × 1 ) over ( 15 × 1 )
22 × 1
15 × 1
+ ( 4 × 3 ) over ( 5 × 3 )
4 × 3
5 × 3
= 22 over 15
22
15
+ 12 over 15
12
15
15 is the least common multiple of denominators 15 and 5. Use it to convert to equivalent fractions with this common denominator.
Step 2 of 3: Add, sub-step b: Add.
Add
22 over 15
22
15
+ 12 over 15
12
15
= ( 22 + 12 ) over 15
22 + 12
15
= 34 over 15
34
15
Step 2 of 3: Add.Hide
Step 3 of 3: Simplify.
Simplify
34 over 15
34
15
= 2 and 4 over 152
4
15
Step 3 of 3: Simplify, sub-step a: Reduce fraction to lowest terms.
Reduce fraction to lowest terms
1 is the greatest common divisor of 34 and 15. The result can't be further reduced.
Step 3 of 3: Simplify, sub-step b: Convert improper fraction to mixed number.
Convert improper fraction to mixed number
34 over 15
34
15
= 2 and 4 over 152
4
15
34 ÷ 15 = 2 remainder 4
One way is to round the numbers to nearest five. (586 - 321 will be 585-320). Another way is to round it off by tens. (586 - 320 will be 590-320). Hopefully this helps you and god luck!
This will be:
[√9]/[(3-2i)+(1+5i)]
simplifying the above we get:
√9/(3+1-2i+5i)
=√9/(4+3i)
rationalizing the denominator we get:
√9/(4-3i)×(4-3i)/(4-3i)
=[√9(4-3i)]/(16+9)
=[3(4-3i)]/25
=(12-9i)/25
Answer: (12-9i)/25
Answer:
no
Step-by-step explanation:
no, because 24 is not divisible by five. If you divide 24/5, you will be left with 4+4/5, and you can't have 4/5 of a piece and have them all be the same length
Answer:
Step-by-step explanation:
The given number is 
We need to write this number in standard form.
Any no is given in the standard form is given by :
Where
a and b is real no and integer
It means,
Hence, this is the required solution.
