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disa [49]
3 years ago
5

Find the tangent line approximation for 10+x−−−−−√ near x=0. Do not approximate any of the values in your formula when entering

your answer below.
Mathematics
1 answer:
Svetllana [295]3 years ago
8 0

Answer:

L(x)=\sqrt{10}+\frac{\sqrt{10}}{20}x

Step-by-step explanation:

We are asked to find the tangent line approximation for f(x)=\sqrt{10+x} near x=0.

We will use linear approximation formula for a tangent line L(x) of a function f(x) at x=a to solve our given problem.

L(x)=f(a)+f'(a)(x-a)

Let us find value of function at x=0 as:

f(0)=\sqrt{10+x}=\sqrt{10+0}=\sqrt{10}

Now, we will find derivative of given function as:

f(x)=\sqrt{10+x}=(10+x)^{\frac{1}{2}}

f'(x)=\frac{d}{dx}((10+x)^{\frac{1}{2}})\cdot \frac{d}{dx}(10+x)

f'(x)=\frac{1}{2}(10+x)^{-\frac{1}{2}}\cdot 1

f'(x)=\frac{1}{2\sqrt{10+x}}

Let us find derivative at x=0

f'(0)=\frac{1}{2\sqrt{10+0}}=\frac{1}{2\sqrt{10}}

Upon substituting our given values in linear approximation formula, we will get:

L(x)=\sqrt{10}+\frac{1}{2\sqrt{10}}(x-0)  

L(x)=\sqrt{10}+\frac{1}{2\sqrt{10}}x-0

L(x)=\sqrt{10}+\frac{\sqrt{10}}{20}x

Therefore, our required tangent line for approximation would be L(x)=\sqrt{10}+\frac{\sqrt{10}}{20}x.

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How do you write 3 7/10 as a decimal
Leokris [45]

Answer:

3.7

Step-by-step explanation:

To change a fraction to a decimal, just divide the numerator with the denominator. Instead of placing the remainder over the divisor, continue to solve until it is answered (unless it's a repeating decimal.)

Divide 7 with 10:

7/10 = 0.7

Remember that there is a whole number, 3. Add that to the decimal you have gotten:

3 + 0.7 = 3.7

3.7 is your answer.

~

8 0
3 years ago
On Saturday Keisha rand 2.536 km on Sunday she ran 1.55 km how much for the did she run on Saturday then on Sunday
Butoxors [25]

Answer:

4.086 or rounded to 4.1

Step-by-step explanation

Since we need to combine the amounts he ran on each day we need to add. We need to add normally and then add the decimal after the number 4. make sure to add km at the end to label your answer.

4 0
2 years ago
Read 2 more answers
When solving negative one over five -1/5 (x − 25) = 7, what is the correct sequence of operations
aleksandr82 [10.1K]

The solution would be like this for this specific problem:

 

\left( { - 5} \right)
\cdot \left( { - \frac{1}{5}} \right) \cdot \left( {x - 25} \right) = 7 \cdot
\left( { - 5} \right)

 

 

\left( { - 5} \right)
\cdot \left( { - \frac{1}{5}} \right) = 1

 

The correct sequence of operations when solving negative one over five (x − 25) = 7 would be multiply each side by −5, and adding 25 to each side.

5 0
3 years ago
What are the coordinates of the orthocenter of △JKL with vertices at J(−4, −1) , K(−4, 8) , and L(2, 8) ?
kompoz [17]

Answer:

K(-4,8) is the ortho center.

Step-by-step explanation:

In a right angled triangle, The vertex of the right angle is the ortho center.

Here we are given

J(-4,-1), K(-4,8) & L(2,8)

Using distance formula we get

JK^{2}= (-4+4)^{2}+ (8+1)^{2}=0+81=81

KL^{2}= (-4-2)^{2}+ (8+-8)^{2}=36+0=36

JL^{2}= (-4-2)^{2}+ (8+1)^{2}=36+81=117

So we can say that

JK^2 + KL^2=JL^2

By converse of pythagorean theorem we get

Hence the Vertex of the right angle is K(-4,8)

K(-4,8) is the ortho center.

7 0
3 years ago
Briley has 347 marbles. Joey has 4 times as many as Briley. Carson has 799 fewer than Joey. How many marbles does Carson have?
Nadya [2.5K]

Answer:

697 marbles

Step-by-step explanation:

We know:

Briley- 374 marbles

Joey- 374*4

Carson- (374*4)-799

Solve:

374*4= 1496 (This is how many Joey has)

1496-799= 697 (This is how many Carson has)

Hope this helps!

6 0
3 years ago
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