3 years ago

F+3.8=9.2 in simplest form

Mathematics

1 answer:

Rom4ik [11]3 years ago

7 0

Just isolate f.. buy getting it alone on one side or the other

You might be interested in

Can someone please check this (#4) for me?

IrinaVladis [17]

Answer:

What you are doing wrong is that you are using the formula to find the area of the entire circle rather than using the formula to find a sector of a circle. The two cases uses 2 different kind sentences of formulas.

3 0

3 years ago

Solve:m+ 2/3=1/2 A. 1 1/6 B. 1/6 C.-1 D. - 1/6

natita [175]

Answer:

D. - 1/6

Step-by-step explanation:

M + 2/3 = 1/2

M = 1/2 - 2/3

$\frac{1}{2} - \frac{2}{3} = \frac{3}{6} - \frac{4}{6} = -\frac{1}{6}$

6 0

3 years ago

Read 2 more answers

-3p + 8 = -13 HELLLLPP

ella [17]

Answer:

p=-7 :)

Step-by-step explanation:

-13-8=3p

-13+(-8)=3p

-21=3p

÷3

-7=p

5 0

3 years ago

34(5f−3)=38 How do i find the value of f?

Oduvanchick [21]

f=14/17 or 0.82352941

8 0

3 years ago

Read 2 more answers

A lamina with constant density rho(x, y) = rho occupies the given region. Find the moments of inertia Ix and Iy and the radii of

jenyasd209 [6]

Answer:

Ix = Iy = $\frac{ρπR^{4} }{16}$

Radius of gyration x = y = $\frac{R}{4}$

Step-by-step explanation:

Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.

Mass of disk = ρπR2

Moment of inertia about its perpendicular axis is $\frac{MR^{2} }{2}$ . Moment of inertia of quarter disk about its perpendicular is $\frac{MR^{2} }{8}$ .

Now using perpendicular axis theorem, Ix = Iy = $\frac{MR^{2} }{16}$ = $\frac{ρπR^{4} }{16}$ .

For Radius of gyration K, equate MK2 = MR2/16, K= R/4.

3 0

3 years ago