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Fofino [41]
3 years ago
12

Arithmetic of Functions problem Open ended

Mathematics
2 answers:
VladimirAG [237]3 years ago
3 0

Answer: <em>(gºh)(25)=2</em>


Step-by-step explanation:

1. This exercise is about Composition of functions, then you have:

2. Then, you have that

<em>(gºh)(25)</em>=g(h(x))=\sqrt{x}-3

3. Now, you must substitute 25 into the function, as you can see below:

<em>(gºh)(25)</em>=\sqrt{25}-3

4. Simplify the fucntion.

5. Therfore, you obtain:

<em>(gºh)(25)</em>=5-3=2


elena55 [62]3 years ago
3 0

Answer:

(g°h)(25) = 2

Step-by-step explanation:

We have given two functions.

Firstly, we have to find two composition of two functions and secondly, we have to find (g°h)(25).

g(x) = x-3 and h(x) = √x

(g°h)(x) = g(h(x))

Putting given values in above formula,we have

(g°h)(x) = g(√x)

(g°h)(x) = √x-3

Putting x = 25 in above equation, we get

(g°h)(25) = √25-3

(g°h)(25) = 5-3

(g°h)(25) = 2

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