Arithmetic of Functions problem Open ended

Mathematics

2 answers:

VladimirAG [237]2 years ago

3 0

Answer: (gºh)(25)=2

Step-by-step explanation:

1. This exercise is about Composition of functions, then you have:

2. Then, you have that

(gºh)(25) $=g(h(x))=\sqrt{x}-3$

3. Now, you must substitute 25 into the function, as you can see below:

(gºh)(25) $=\sqrt{25}-3$

4. Simplify the fucntion.

5. Therfore, you obtain:

(gºh)(25) $=5-3=2$

elena55 [62]2 years ago

3 0

Answer:

(g°h)(25) = 2

Step-by-step explanation:

We have given two functions.

Firstly, we have to find two composition of two functions and secondly, we have to find (g°h)(25).

g(x) = x-3 and h(x) = √x

(g°h)(x) = g(h(x))

Putting given values in above formula,we have

(g°h)(x) = g(√x)

(g°h)(x) = √x-3

Putting x = 25 in above equation, we get

(g°h)(25) = √25-3

(g°h)(25) = 5-3

(g°h)(25) = 2

You might be interested in

Simplify the given expression below 4/3-2i

ANTONII [103]

So-called simplifying, really means, "rationalizing the denominator", which is another way of saying, "getting rid of that pesky radical in the bottom"

$\bf \cfrac{4}{3-2i}\cdot \cfrac{3+2i}{3+2i}\impliedby \textit{multiplying by the conjugate of the bottom}
\\\\\\
\cfrac{4(3+2i)}{(3-2i)(3+2i)}\implies \cfrac{4(3+2i)}{3^2-(2i)^2}\implies \cfrac{4(3+2i)}{3^2-(4i^2)}\\\\
-------------------------------\\\\
recall\qquad i^2=-1\\\\
-------------------------------\\\\
\cfrac{4(3+2i)}{3^2-(4\cdot -1)}\implies \cfrac{4(3+2i)}{9+4}\implies \cfrac{12+8i}{13}\implies \cfrac{12}{13}+\cfrac{8}{13}i$