First, determine the number of computers that are needed for 924 students.
n = (924 students)(5 computers / 12 students)
n = 385 computers
Since, there are only 125 computers, the difference can be calculated.
d = 385 computers - 125 computers
d = 260 computers
Hence, 260 more computers are still needed.
y+z=10
x+z=8
x+y=12
(y+z)-(x+z)=10-8
y-x=2
y-x=2
y+x=12
solve simultaneously
x=5, y=7
then substitute to get z=3
hence xyz=573
Answer:
Step-by-step explanation:
f(x)=2(x-2)²-5
f(x)=2(x²-4x+4)-5
f(x)=2x²-8x+3
Answer:
1/6
Step-by-step explanation:
