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kotykmax [81]
3 years ago
7

bobby’s christmas list had 3 more than twice as many items on it than johnny’s list. johnny asked for 8 fewer items than bobby.

how many items were on johnny’s (x) and bobby’s (y) christmas lists?
Mathematics
1 answer:
Nataly [62]3 years ago
3 0

Answer:

<em>Johnny had </em><em>5</em><em> items and Bobby had </em><em>13</em><em> items.</em>

Step-by-step explanation:

Let us assume that Johnny has x items and Bobby has y items in their list.

Bobby had 3 more than twice as many items on it than Johnny. So,

\Rightarrow y=3+2x  ----------1

Johnny asked for 8 fewer items than bobby. So,

\Rightarrow y-8=x  -----------2

Putting the value of x from equation 2 in equation 1, we get

\Rightarrow y=3+2(y-8)

\Rightarrow y=3+2y-16

\Rightarrow 2y-y=16-3

\Rightarrow y=13

Putting the value of y in equation 2,

\Rightarrow 13-8=x

\Rightarrow x=5

So, Johnny had 5 items and Bobby had 13 items.

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Answer:

The claim made by the researcher lacks the validity on basis of reasons as indicated in the explanation.

Step-by-step explanation:

The claim made by the researcher is not valid on basis of following reasons:

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Find the circumference of a circle whose area is 24
zalisa [80]

The answer is: " 17.35 " .

__________________________________

→ The circumference of the circle is: " 17.35 units " .

__________________________________


The area, "A", of a circle:

A = \pi * r² ;

Note: \pi  = 3.14 .

The area of the circumference, "C", of a circle:

C = 2 \pi r .

__________________________________________

Given:

A = 24 ;

Use the formula for the area, "A" of a circle, to find the radius, "r" .

Then, plug the value obtained for "r" into the formula for the circumference, "C" , of a circle:

C = 2\pi r l

To solve for the circumference, "C", of the circle.

________________

A = \pi  *  r^{2} ;

24 = 3.14 * r² ;

↔ 3.14 * r² = 24 ;

Divide each side of the equation by "(3.14)" ;

[3.14 * r²] / 3.14 = (24) / (3.14) ;

to get:

→ r² = 7.64331210191 ;

Take the positive square root of each side of the equation;

to isolate "r" on one side of the equation; & to solve for the radius, "r" ;

→ ⁺√(r²) = ⁺√(7.64331210191) ;

to get:

→ r = 2.76281034802 ;

____________________________

Now, plug this "obtained value" for the radius, "r" into the equation for the formula for the circumference, "C" of a circle:

→ C = 2 \pi * r ;

to solve for the circumference, "C", of the circle:

→ C = 2 * (3.14) * (2.76281034802) ;

= (6.28) * (2.76281034802) ;

= 17.3504489856 ;

→ round to: " 17.35 units" .

__________________________________

The answer is: " 17.35 " .

__________________________________

→ The circumference of the circle is: " 17.35 units " .

__________________________________

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s344n2d4d5 [400]

Answer:

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Step-by-step explanation:

I like to use a graphing calculator for finding the zeros of higher order polynomials. The attachment shows them to be at x = -3, -1, +2.

__

The zeros can also be found by trial and error, trying the choices offered by the rational root theorem: ±1, ±2, ±3, ±6. It is easiest to try ±1. Doing so shows that -1 is a root, and the residual quadratic is ...

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