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3 years ago

7

Add the following numbers and use the checking method (add down and then add up) to make sure your answer is correct. (Copy care

fully on scratch paper to work the problem.)
471
+
582

1 answer:

pogonyaev3 years ago

6 0

Answer:

1053

Step-by-step explanation:

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kompoz [17]

Hey you're answer is

18 cm

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2 years ago

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How do you write a sentence about comparing the values of the nines in the number 199,204

Margarita [4]

Answer:

Step-by-step explanation:

The first 9 stands for 90,000 and the second for 9 000 so the first 9 is worth

90,000 / 9,000 equals 10 times the second one.

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3 years ago

A man driving a minivan leaves his home and travels north 5 miles, then turns right and travels east 12 miles, arriving at his p

Zepler [3.9K]

Answer:

The distance between house to work is 13 miles .

Step-by-step explanation:

Given as :

The distance that man travel to north = OA = 5 miles

Now, From north ,man turn right and travel to east

So, The distance that man travel to east = AB = 12 miles

Let The distance between house to work = x miles

So, x miles is the displacement from north to east direction

i.e x = $\sqrt{OA^{2} + AB^{2} }$

Or, x = $\sqrt{5^{2} + 14^{2} }$

Or, x = $\sqrt{169 }$

∴ x = 13

So, The distance between house to work = x = 13 miles

Hence, The distance between house to work is 13 miles . Answer

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2 years ago

Find the zeros of y = x2 – 6x – 4 by completing the square.

katrin [286]

Answer:

The solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

Step-by-step explanation:

Given the function

$y\:=\:x^2\:-\:6x\:-\:4$

substitute y = 0 in the equation to determine the zeros

$0\:=\:x^2\:-\:6x\:-\:4$

Switch sides

$x^2-6x-4=0$

Add 4 to both sides

$x^2-6x-4+4=0+4$

Simplify

$x^2-6x=4$

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

$x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2$

$x^2-6x+\left(-3\right)^2=13$

Apply perfect square formula: (a-b)² = a²-2ab+b²

$\left(x-3\right)^2=13$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-3=\sqrt{13}$

Add 3 to both sides

$x-3+3=\sqrt{13}+3$

Simplify

$x=\sqrt{13}+3$

now solving

$x-3=-\sqrt{13}$

Add 3 to both sides

$x-3+3=-\sqrt{13}+3$

Simplify

$x=-\sqrt{13}+3$

Thus, the solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

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2 years ago

Which of the following best describes the relationship between (x+1) and the polynomial x^2-x-2?

elena-14-01-66 [18.8K]

I believe that you could factor (x+1) out of the polynomial

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