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3 years ago

How to Estimate √40 to the nearest tenth.

Mathematics

1 answer:

notka56 [123]3 years ago

7 0

Answer:

Square Root of 40 to the Nearest Tenth

Square Root to the nearest tenth

Square Root of 40 to the nearest tenth, means to calculate the square root of 40 where the answer should only have one number after the decimal point.

Here are step-by-step instructions for how to get the square root of 40 to the nearest tenth:

Step 1: Calculate

We calculate the square root of 40 to be:

√40 = 6.32455532033676

Step 2: Reduce

Reduce the tail of the answer above to two numbers after the decimal point:

6.32

Step 3: Round

Round 6.32 so you only have one digit after the decimal point to get the answer:

6.3

To check that the answer is correct, use your calculator to confirm that 6.32 is about 40.

Step-by-step explanation:

Pls mark brainliest tyy!!

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It takes 10 people 15 hours to prepare the gym for the school dance. How many hours would it take 12 people to prepare the gym?

valentinak56 [21]

Answer

18 hours

Step-by-step explanation:

if 10 people spend 15 hours

one person spend 15/10=1.5

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2 years ago

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3 years ago

The height of a tennis ball tossed into the air is modeled by h(x) = 40x â€" 16x 2, where x is elapsed time in seconds. During w

egoroff_w [7]

The time interval x >0.5 and x > 2.04 will the tennis ball be at least 15 feet above the ground.

Given that,

The height of a tennis ball tossed into the air is modeled by,

$\rm h(x) = 40x - 16x^2$

Where x is elapsed time in seconds.

We have to determine,

During what time interval will the tennis ball be at least 15 feet above the ground?

According to the question,

The height of a tennis ball tossed into the air is modeled by,

$\rm h(x) = 40x - 16x^2$

Where x is elapsed time in seconds.

Then,

When the tennis ball be at least 15 feet above the ground,

$h(x) = 15$

Substitute the value of h(x) in the equation,

$\rm h(x) = 40x - 16x^2\\\\ 15 = 40x - 16x^2\\\\ 16x^2-40x+15=0$

Factorize the equation for finding the time interval will the tennis ball be at least 15 feet above the ground is,

$\rm 16x^2-40x+15= 0\\\\x = \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\x = \dfrac{-(-40)\pm \sqrt{(-40)^2-4 \times 16 \times 15}}{2 \times 16}\\\\x = \dfrac{-(-40)\pm \sqrt{1600- 960}}{32}\\\\x = \dfrac{40\pm \sqrt{640}}{32}\\\\x = \dfrac{40 + 25.29}{32} \\\\x = \dfrac{40 + 25.29}{32} \ and \ x = \dfrac{40 - 25.29}{32}\\\\x = \dfrac{65.29}{32} \ and \ x = \dfrac{14.71}{32}\\\\x = 2.04 \ and \ x = 0.45$