The completely factored expression of 2x^2 + 4x + 3xy + 6y is (2x + 3y)(x + 2)
<h3>How to factor the polynomial?</h3>
The expression is given as:
2x^2 + 4x + 3xy + 6y
Group the expression into two
[2x^2 + 4x] + [3xy + 6y]
Factor out each group
2x(x + 2) + 3y(x + 2)
Factor out x + 2
(2x + 3y)(x + 2)
Hence, the completely factored expression of 2x^2 + 4x + 3xy + 6y is (2x + 3y)(x + 2)
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Answer:
the desired range is 0° < angle < 180°
Step-by-step explanation:
If 2x were just slightly less than b, then the angle opposite the base would be just less than 180 degrees.
The larger the value of x, the further the intersection of the two congruent sides is moved away from the base b. The angle between these two congruent sides would approach but never equal zero.
Thus, the desired range is 0° < angle < 180°
Answer:
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Step-by-step explanation:
