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Dmitry_Shevchenko [17]
3 years ago
11

________ is the name for when a director decides where and when performers move and position themselves on the stage.

Physics
1 answer:
Maurinko [17]3 years ago
5 0

Answer:

Blocking/staging

Explanation:

Blocking/staging is the name for when a director decides where and when performers move and position themselves on the stage.

Moreover, Blocking a dream sequence is merely "working on the details of an actor's movements with regard to the camera." We can also reckon of blocking as the dance routines of a dance or a ballet: all the components on the set must move in perfect sync with one another (performers, extras, automobiles, crew, machinery).

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A small town is located near a body of water, and enjoys cooler temperatures than other areas in the same climate zone. This is
Lapatulllka [165]
C- microclimate or either d- climate zone.
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3 years ago
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How much electrical energy is used by a 400 W toaster that is operating for 5
Setler [38]

Answer:

The electrical energy consumed by a toaster is 0.033 Kwh.

Explanation:

The power utilized by the toaster is 400 W.

The toaster is operated for 5 Minutes.

We know that,

Substitute the values in the above formula to obtain electrical energy,

Electrical energy = 0.4 × 0.083

Electrical energy is 0.033 Kwh.

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3 years ago
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Phil is riding a scooter and pushes off the ground with his foot. this causes him to accelerate at 12 m /s. Phil weighs 600 N. h
Dvinal [7]

Answer:

734.16 kg m/s^{2}

Explanation:

The problem is asking for the Force of pushing off the ground.

  • The formula of Force is: F = mass x acceleration

Given = <em>Mass</em>: 600 newtons (N)

             <em>Acceleration</em>: 12 m/s^{2}

We have to convert the mass into kg first. Remember that <u>1 kg is equal to 9.80665 newtons.</u>

Let x be the<em> mass in newtons</em>.

Let's convert: \frac{1 kg}{9.80665 N} x \frac{x}{600 N} = \frac{600}{9.80665} = 61.18 kg

Phil's weight is 61.18 kg

Let's go back to finding the force.

F = m x a

F = 61.18 kg x 12 m/s^{2}

F = 734.16 kg m/s^{2}

7 0
3 years ago
Assuming that voltage remains constant, what happens to the current in a filament if it is replaced by a longer wire?
Elena L [17]

Answer:

Choice B: The current decreases.

Explanation:

The resistance of a conductor is proportional to its length when radius and resistivity stays the same. The resistance of the longer filament will be greater than the resistance of the initial one.

For Ohmic conductors,

\displaystyle I = \frac{V}{R},

where

  • I is the current through the conductor,
  • V is the voltage across the conductor, and
  • R is the resistance of the conductor.

Voltage here stays the same. Increasing the resistance R of the conductor will reduce the current.

The filament might heat up over time. The filament might not be an ohmic conductor. Still, a similar trend shall exist. Resistance will be greater in the longer filament, and current will decrease.

4 0
4 years ago
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The maximum Compton shift in wavelength occurs when a photon isscattered through 180^\circ .
vlabodo [156]

Answer: 90\°

Explanation:

The Compton Shift \Delta \lambda in wavelength when the photons are scattered is given by the following equation:

\Delta \lambda=\lambda_{c}(1-cos\theta)     (1)

Where:

\lambda_{c}=2.43(10)^{-12} m is a constant whose value is given by \frac{h}{m_{e}c}, being h the Planck constant, m_{e} the mass of the electron and c the speed of light in vacuum.

\theta) the angle between incident phhoton and the scatered photon.

We are told the maximum Compton shift in wavelength occurs when a photon isscattered through 180\°:

\Delta \lambda_{max}=\lambda_{c}(1-cos(180\°))     (2)

\Delta \lambda_{max}=\lambda_{c}(1-(-1))    

\Delta \lambda_{max}=2\lambda_{c}     (3)

Now, let's find the angle that will produce a fourth of this maximum value found in (3):

\frac{1}{4}\Delta \lambda_{max}=\frac{1}{4}2\lambda_{c}(1-cos\theta)      (4)

\frac{1}{4}\Delta \lambda_{max}=\frac{1}{2}\lambda_{c}(1-cos\theta)      (5)

If we want \frac{1}{4}\Delta \lambda_{max}=\frac{1}{2}\lambda_{c}, 1-cos\theta   must be equal to 1:

1-cos\theta=1   (6)

Finding \theta:

1-1=cos\theta

0=cos\theta  

\theta=cos^{-1} (0)  

Finally:

\theta=90\°    This is the scattering angle that will produce \frac{1}{4}\Delta \lambda_{max}      

7 0
3 years ago
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