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3 years ago

Find initial velocity and time in air

Physics

1 answer:

kkurt [141]3 years ago

6 0

Answer:

The answer to your question is: v = 121.46 m/s

Explanation:

Data

h = 30 m

vo = ?

dx = 300 m

Formula

t = $\sqrt{\frac{2h}{g}}$

speed = distance / time

Process

$t = \sqrt{\frac{2(30)}{9.81}} \\$

t= 2.47 s

speed = 300 / 2.47

speed = v = 121.46 m/s

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4 years ago

What happens when light is allowed to pass through a suspension

Nutka1998 [239]

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4 years ago

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How much work is done (by a battery, generator, or some other source of potential difference) in moving Avogadro's number of ele

luda_lava [24]

Answer:

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Explanation:

First, we calculate the potential difference between the given 2 points. So, we have:

V₁ = Electric Potential at Initial Position = 6.7 V

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ΔV = Potential Difference = V₂ - V₁ = -8.9 V - 6.7 V = - 15.6 V

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ΔV = 15.6 V

Now, we calculate total charge:

Total Charge = q = (No. of Electrons)(Charge on 1 Electron)

where,

No. of Electrons = Avagadro's No. = 6.022 x 10²³

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Therefore,

q = (6.022 x 10²³)(1.6 x 10⁻¹⁹ C)

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Now, from the definition of potential difference, we know that it is equal to the worked done on a unit charge moving it between the two points of different potentials:

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3 years ago

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lana66690 [7]

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4 years ago

A batter hits a 0.140-kg baseball that was approaching him at 50.0 m/s and, as a result, the ball leaves the bat at 35.0 m/s in

KonstantinChe [14]

Answer:

Impulse, J = 2.1 kg-m/s

Explanation:

Given that,

Mass of baseball, m = 0.14 kg

It was approaching him at 50.0 m/s and, as a result, the ball leaves the bat at 35.0 m/s in the direction of the pitcher. We need to find the magnitude of Impulse delivered to the baseball.

The change in momentum is equal to the Impulse imparted to the ball i.e.

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So, the Impulse delivered to the baseball is 2.1 kg-m/s

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4 years ago

Find initial velocity and time in air​

Find initial velocity and time in air