Answer:
τ ≈ 0.90 N•m
F =
Explanation:
I = ½mR² = ½(10)0.5² = 1.25 kg•m²
α = ω²/2θ = 3.0² / 4π = 0.716... rad/s²
τ = Iα = 1.25(0.716) = 0.8952... ≈ 0.90 N•m
τ = FR
Now we have the unanswered question of reference frame.
80° from what?
If it's 80° from the radial
F = τ/Rsinθ = 0.90/0.5sin80 = 1.818... ≈ 1.8 N
If it's If it's 80° from the tangential
F = τ/Rcosθ = 0.90/0.5cos80 = 10.311... ≈ 10 N
There are an infinite number of other potential solutions
Answer:
It is important to note, that the 2nd Law of thermodynamics plays no fundamental role in answering this question; we need a heat sink because the entropy is a state function, and at the end of the reversible process (which is visualized through the Carnot cycle diagram relevant for this problem), the entropy value of the system must return to the value it had originally.
Answer:
The final speed of the train car is 8.57 m/s.
Explanation:
Given that,
Mass of train car = 1000 kg
Mass of sand = 400 kg
Speed of train car = 12 m/s
We need to calculate the final speed of the train car after the sand is dumped
Using conservation of momentum
...(I)
Put the value in the equation (I)
Hence, The final speed of the train car is 8.57 m/s.
Answer:
All are not true.
Explanation:
Sound needs medium to travel.
sound speed is fastest in solids.
