<h3>
Answer: 0.6</h3>
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Work Shown:
sin(angle) = opposite/hypotenuse
sin(T) = VU/VT
sin(T) = 3/5
sin(T) = 0.6
Answer: The required matrix is
![T=\left[\begin{array}{ccc}-1&3\\2&4\end{array}\right] .](https://tex.z-dn.net/?f=T%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%263%5C%5C2%264%5Cend%7Barray%7D%5Cright%5D%20.)
Step-by-step explanation: We are given to find the transition matrix from the bases B to B' as given below :
B = {(-1,2), (3, 4)) and B' = {(1, 0), (0, 1)}.
Let us consider two real numbers a, b such that

Again, let us consider reals c and d such that

Therefore, the transition matrix is given by
![T=\left[\begin{array}{ccc}-1&3\\2&4\end{array}\right] .](https://tex.z-dn.net/?f=T%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%263%5C%5C2%264%5Cend%7Barray%7D%5Cright%5D%20.)
Thus, the required matrix is
![T=\left[\begin{array}{ccc}-1&3\\2&4\end{array}\right] .](https://tex.z-dn.net/?f=T%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%263%5C%5C2%264%5Cend%7Barray%7D%5Cright%5D%20.)
There is no question? ...
Answer:
{HH,CC,HC,CH}
Step-by-step explanation:
We are given that
H denotes hot and cloudy denotes C.
We have to find the total possible outcomes for the weather on two consecutive days.
The possible cases in two consecutive days
Both days are hot=HH
Both days are cloud=CC
First day is hot other day cloudy=HC
First day is cloudy other day is hot=CH
Total possible cases=HH,CC,HC,CH
Therefor, the total outcomes for the weather on two consecutive days={HH,CC,HC,CH}