Answer:
C
Explanation:All the other answers are wrong
Answer:
1.400 mol
Explanation:
To convert grams to moles, you will need the molar mass. The molar mass of iron(iii) sulfate is 399.88 g/mol. Divide grams by the molar mass to find moles.
(560.0 g)/(399.88 g/mol) = 1.400 mol
There are 1.400 mol present in 560.0 g of iron(iii) sulfate.
Answer:
1.non electrolytes
2.electrolytes
3.non electrolytes
4.electrolytes
5.electrolytes
6.electrolytes
Explanation:
electrolytes are substance in their molten form which can be decomposed by the passage of electricity exay includes acids,base and salts etc were as non electrolytes cannot be decomposed by the passage of electricity example alcohol,sugar organic solvents etc. Electrolytes in the body like potassium, sodium in their molten form helps to keep the electrical circuitry of the heart well
Answer:
25cm³ = 0.025L of H2So4
Molarity of H2SO4 = 1moldm-³
Recall ... 1dm-³ = 1L
So the Molarity can also be 1mol/L
Mole = Molarity x volume in L
Mole of H2SO4 = 1mol/L x 0.025L
=0.025Moles of Sulphuric acid reacted.
From the equation of reaction
1mole of H2SO4 reacts to produce 1mole of Copper sulphate crystal
Since their Mole ratio is 1:1
It means that Since 0.025mole of H2SO4 reacted.... 0.025mole of CuSO4.5H2O would be produced
Nice.. OK
So we know the moles of CuSO4.5H2O produced
We can get the Mass
Recall
From
Mole=Mass/Molar Mass
Mass = Mole x Molar Mass
Molar Mass of CuSO4.5H2O = 64 + 32 + 16x4+ 5(2+16)
Mm= 250g/mol
Mass = 0.025mol x 250g/mol
= 6.25g of CuSO4.5H2O crystals Would be PRODUCED.
Answer:
You can increase your precision in the lab by paying close attention to detail, using equipment properly and increasing your sample size. Ensure that your equipment is properly calibrated, functioning, clean and ready to use.
