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ikadub [295]
3 years ago
9

What is it called when you apply science and mathematics to real life problems

Chemistry
1 answer:
Ghella [55]3 years ago
8 0

Answer:

I think S.T.E.M but i'm not 100% sure

Explanation:

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Pls help, How is stoichiometry used to calculate amounts of substances in a chemical reaction?
Elden [556K]

Answer:

Thus, to calculate the stoichiometry by mass, the number of molecules required for each reactant is expressed in moles and multiplied by the molar mass of each to give the mass of each reactant per mole of reaction. The mass ratios can be calculated by dividing each by the total in the whole reaction.

Explanation: Stoichiometry is the field of chemistry that is concerned with the relative quantities of reactants and products in chemical reactions. For any balanced chemical reaction, whole numbers (coefficients) are used to show the quantities (generally in moles ) of both the reactants and products.

7 0
2 years ago
Answer soon please ​
erica [24]

Answer:

The sphere on the left as it has more mass.

Explanation:

Inertia is the resistance to changes of motion.

5 0
3 years ago
Oxygen in the air can react with wood when a match is burned. Ash is produced.
Hitman42 [59]

Answer:

D. Ash is a different substance than wood.

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2 years ago
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What is the Mechanical advantage of a machine that only changes the direction of the force?
Sloan [31]

Answer: 1

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The number of times a machine increases a force exerted on it The input force will be the same as the output force.

6 0
3 years ago
Hydrochloric acid reacts with sodium hydroxide to produce sodium chloride and water. If 20.6 g of sodium hydroxide reacts with a
astraxan [27]

Answer:

30.1 g NaCl

Explanation:

Your first conversion is converting grams NaOH to moles of NaOH using its molar mass (39.997 g/mol). Then, use the mole ratio of 1 mol NaCl for every 1 mol NaOH to get to moles of NaCl. Then finally multiply by the molar mass of NaCl (58.44 g/mol) to get grams of NaCl.

20.6 g NaOH • (1 mol NaOH / 39.997 g NaOH) • (1 mol NaCl / 1 mol NaOH) • (58.44 g NaCl / 1 mol NaCl) = 30.1 g NaCl

4 0
2 years ago
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