Answer:
25cm³ = 0.025L of H2So4
Molarity of H2SO4 = 1moldm-³
Recall ... 1dm-³ = 1L
So the Molarity can also be 1mol/L
Mole = Molarity x volume in L
Mole of H2SO4 = 1mol/L x 0.025L
=0.025Moles of Sulphuric acid reacted.
From the equation of reaction
1mole of H2SO4 reacts to produce 1mole of Copper sulphate crystal
Since their Mole ratio is 1:1
It means that Since 0.025mole of H2SO4 reacted.... 0.025mole of CuSO4.5H2O would be produced
Nice.. OK
So we know the moles of CuSO4.5H2O produced
We can get the Mass
Recall
From
Mole=Mass/Molar Mass
Mass = Mole x Molar Mass
Molar Mass of CuSO4.5H2O = 64 + 32 + 16x4+ 5(2+16)
Mm= 250g/mol
Mass = 0.025mol x 250g/mol
= 6.25g of CuSO4.5H2O crystals Would be PRODUCED.
