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Anna11 [10]
3 years ago
12

Starting at sea level, a submarine descends at a constant rate to a depth of −5/6 mile relative to sea level in 4 minutes. What

was the submarine's depth relative to sea level after the first minute?
(NOTE: there are no answer choices)
Mathematics
2 answers:
Vinil7 [7]3 years ago
8 0

I'm pretty sure it would be -5/24

vaieri [72.5K]3 years ago
7 0

Answer:

Submarine's depth after first minute will be -\frac{5}{24}

Step-by-step explanation:

Submarine is descending at a constant rate = -\frac{5}{6} miles in 4 minutes

Therefore, after the first minute submarine's depth relative to the sea level will be

= \frac{\text{Rate at which submarine is descending}}{\text{Time taken}}

= -\frac{5}{6\times 4}

= -\frac{5}{24}

Therefore, submarine's depth after first minute will be -\frac{5}{24}

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Answer: 12√2

Step-by-step explanation:

This is a 45-45-90 triangle. In this triangle, a and b are equal lengths, therefore hypotenuse, c, is x√2.

Since a and b is 12, c is 12√2.

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3 years ago
Kelly and Daniel wrote the following proofs to prove that vertical angles are congruent. who is correct?
katrin [286]
Kelly? Im not sure actually... Im going with Kelly but im probably wrong
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3 years ago
Read 2 more answers
The point (-7,4) is reflected over the line x=-3. Then the resulting point is reflected over the line y=x. Where is the point lo
Ne4ueva [31]

Answer:

  (4, 1)

Step-by-step explanation:

Since the first reflection is over the vertical line x=-3, the y-coordinate remains the same. The x-coordinate of A' will make the point (-3, 4) on the line of reflection be the midpoint between A and A':

  (-3, 4) = (A +A')/2

  2(-3, 4) -A = A' = (-6-(-7), 8 -4) = (1, 4)

The reflection over the line y=x simply interchanges the two coordinate values:

  A'' = (4, 1)

3 0
3 years ago
A line with a slope of 6 passes through the points (8,h) and (5,
LenaWriter [7]

\bf (\stackrel{x_1}{8}~,~\stackrel{y_1}{h})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{-8}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-8-h}{5-8}=6\implies \cfrac{-8-h}{-3}=6 \\\\\\ -8-h=-18\implies -8+18=h\implies 10=h

7 0
3 years ago
One pound of swordfish costs as much as 1.5 pounds of salmon. Mrs. O pays $39 for 2 pounds of salmon and 3 pounds of swordfish.
Dimas [21]

Answer:

The ratio of the amount for swordfish to the amount of salmon is 6:4

Step-by-step explanation:

Given as :

The price for 1 pound of swordfish = The price of 1.5 pound of salmon

So, On this relation

The price for ( 1 × 2 ) pound of swordfish = The price of ( 1.5× 2 )  pound of salmon

i.e The price for 2 pound of swordfish = The price of 3 pound of salmon

Now According to question

Mrs. O pay the total money for 2 pounds of swordfish and 3 pound of salmon = $ 39

Let the money she pay for swordfish = 2 sw

And The money she pay for salmon = 3 sa

∵, The total money she pay for both  = $ 39

I.e  2 sw + 3 sa = 39

As 2 sw = 3 sa

So, 3 sa + 3 sa = 39

Or, 6 sa = 39

or, sa = \frac{39}{6} = \frac{13}{2}

∴ sw = \frac{13}{2} × \frac{3}{2}

or, sw = \frac{39}{4}

Now, the ratio of the amount for swordfish to the amount of salmon = \frac{\frac{39}{4}}{\frac{13}{2}}

I.e The ratio = \frac{6}{4}

Hence The ratio of the amount for swordfish to the amount of salmon is 6:4

Answer

3 0
3 years ago
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