1/3 of 12,000 ballots were thrown out.
1/3 * 12,000 = 12,000/3 = 4,000
4,000 ballots were thrown out.
12,000 - 4,000 = 8,000
There were 8,000 ballots left.
1/4 of 8,000 ballots are for candidate A.
1/4 * 8,000 = 8,000/4 = 2,000
Candidate A received 2,000 votes.
8,000 - 2,000 = 6,000
Candidate B received 6,000 votes.
(-2^3) = -8.
-2 times 3 = -6.
The expression is now -6 - (-8).
-6 + 8 = 2.
The answer should be 2.
Answer:
First, find tan A and tan B.
cosA=35 --> sin2A=1−925=1625 --> cosA=±45
cosA=45 because A is in Quadrant I
tanA=sinAcosA=(45)(53)=43.
sinB=513 --> cos2B=1−25169=144169 --> sinB=±1213.
sinB=1213 because B is in Quadrant I
tanB=sinBcosB=(513)(1312)=512
Apply the trig identity:
tan(A−B)=tanA−tanB1−tanA.tanB
tanA−tanB=43−512=1112
(1−tanA.tanB)=1−2036=1636=49
tan(A−B)=(1112)(94)=3316
kamina op bolte
✌ ✌ ✌ ✌
-36-8 = -44
-36+(-8) = -44
third option
