Answer: I would say make a plan so that way you have a better understanding of it. I hope this helps! :)
Is this the full question?
Answer:
int counter = 0;
for(int i =0;i<100;i++){
if(myarr[i]%2==0){
if(myarr[i] > 10 && myarr[i]<157){
counter++;
}
}
}
cout<<counter;
Explanation:
The question is answered using c++ and it assumes that the array name is myarr
This line initializes counter to 0
int counter = 0;
This iterates through the array
for(int i =0;i<100;i++){
This checks if current array element is even number
if(myarr[i]%2==0){
If the above condition is true; This checks if the array element is within the range of 10 and 157 (inclusive)
if(myarr[i] >= 10 && myarr[i]=<157){
If yes, the counter is increased by 1
counter++;
}
}
}
This prints the total counter number
cout<<counter;
