Answer:
there is no common difference. it is not constant.
Answer:
From the graph attached, we know that
by the corresponding angle theorem, this theorem is about all angles that derive form the intersection of one transversal line with a pair of parallels. Specifically, corresponding angles are those which are placed at the same side of the transversal, one interior to parallels, one exterior to parallels, like
and
.
We also know that, by definition of linear pair postulate,
and
are linear pair. Linear pair postulate is a math concept that defines two angles that are adjacent and for a straight angle, which is equal to 180°.
They are supplementary by the definition of supplementary angles. This definition states that angles which sum 180° are supplementary, and we found that
and
together are 180°, because they are on a straight angle. That is, 
If we substitute
for
, we have
, which means that
and
are also supplementary by definition.
Acceleration is simplified by assuming it is the constant -g
a=-g we integrate this with respect to time to get v...
v=-gt+C where C is the initial velocity in this case 14ft/s so
v=-gt+14 integrate again to get the height function
h=(-gt^2)/2 +14t +C we are not given an initial height so C is 0
h(t)=14t-gt^2/2 letting g=32 and neatening up a bit...
h(t)=14t-16t^2
Answer:
Yes
Step-by-step explanation:
you can plug any number from the graph on the line and it's still going to equal something, i'm sorry this is really bad explaing but when it's a straight line you can plug anything in and still get an answer