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Oksanka [162]
2 years ago
9

A rectangular garden is fenced on all sides with 256 feet of fencing. The garden is 8feet longer than it is wide. Find the lengt

h and width of the garden.

Mathematics
1 answer:
Marina86 [1]2 years ago
6 0
Perimeter = 2L + 2W = 256

"8 feet longer than it is wide"
translates to
L = 8 + W

we plug that into the first equation and get
2(8 + W) + 2W = 256
now we solve for W

distribute the 2
16 + 2W + 2W = 256

add like terms
16 + 4W = 256

subtract 16 from both sides
4W = 240

divide both sides by 4
W = 60

plug that into
L = 8 + W
and solve for L now

L = 8 + 60
so
L = 68

therefore your
length = 68
and
width = 60
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Step-by-step explanation:

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Given: LP=NP<br> ML=MN<br> Prove: LQ=QN
julsineya [31]

Answer:

The Proof is below.

Step-by-step explanation:

Given:

\overline {LP} \cong \overline{NP}

\overline {ML} \cong \overline{MN}

To Prove:

\overline {LQ} \cong \overline{QN}

Proof:

In  ΔLPM  and ΔNPM  

\overline {LP} \cong \overline{NP}  ……….{Given}

\overline {ML} \cong \overline{MN}  ……….{Given}

\overline {LP} \cong \overline{NP}  ……….{Reflexive Property}

ΔLPM ≅ ΔNPM      ….{ By Side-Side-Side congruence test}

∴ ∠LMP ≅ ∠NMP  ...{Corresponding parts of congruent triangles (c.p.c.t).}.....( 1 )

Now In ΔLMQ  and ΔNMQ  

\overline {ML} \cong \overline{MN}  ……….{Given}

∠LMQ ≅ ∠NMQ                                 ..........{From 1 above}

\overline {MQ} \cong \overline{MQ}  ……….{Reflexive Property}

ΔLMQ ≅ ΔNMQ         ....{ By Side-Angle-Side Congruence test}

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4 0
2 years ago
#5 Antonio and Abby had the same nimber of paperclips. After Antonio gave 30 paperclips to Abby, Abby had twice as many papercli
Kay [80]

Answer:

#5: 180 paperclips in total.

#6: 126 stamps in total.

#7: Elena should give Lucy 15 colored pencils.

Step-by-step explanation:

This explanation solves each question by setting a single unknown, x.

<h3>#5</h3>

Let x the initial number of paperclips of Antonio. That should also be the number of Abby's paperclips.

Initially:

  • Antonio: x paperclips;
  • Abby: x paperclips.

Antonio gives 30 paperclips to Abby. After that,

  • Antonio: (x - 30) paperclips;
  • Abby: x + 30 paperclips.

Abby now possess twice as many paperclips as Antonio does. In other words,

2(x - 30) = x + 30.

By the distributive property:

2x - 60 = x + 30.

Substract x - 60 from both sides

x = 30 - (-60) = 90.

Both Antonio and Abby initially possess 90 paperclips. That's 180 in total.

<h3>#6</h3>

Similarly, let x be the number of Emily's stamps. That should be the same as the number of Jasmine's stamps.

Initially:

  • Emily: x stamps;
  • Jasmine: x stamps.

After Emily gives 42 stamps to Jasmine:

  • Emily: x-42 stamps;
  • Jasmine: x+42 stamps.

Jasmine now possesses twice as many stamps as Emily does. In other words,

2(x-42) = x+42.

x = 42 + 2\times 42 = 126.

Jasmine used to possess 126 stamps. Now she possesses 126 + 42 = 168 stamps after receiving 42 stamps from Emily.

<h3>#7</h3>

Let the number of pencils that Elena needs to give to Lucy be x.

Initially:

  • Elena: 60 pencils;
  • Lucy: 26 pencils.

After Elena gives x pencils to Lucy:

  • Elena: 60 - x pencils;
  • Lucy: 26 + x pencils.

Elena should now possess four more pencils than Lucy does. In other words,

\underbrace{60 - x}_{\text{Elena's}} = \underbrace{(26 + x)}_{\text{Lucy's}} +4.

2x = 30.

x = 15.

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Answer:

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First of all, how do you buy exactly 15.5 pizzas?
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