Answer;
-The above statement is true.
During a medical screening, lung capacity testing is a standard procedure
Explanation;
-Lung capacity testing also the pulmonary function test is a part of medical screening that is done to diagnose certain types of lung disease, such as asthma, bronchitis, and emphysema. Find the cause of shortness of breath and also measure whether exposure to chemicals at work affects lung function.
The statement that defines the specific heat capacity for a given sample is the quantity of heat that is required to raise 1 g of the sample by 1°C (Kelvin) at a constant pressure.
<h3>What is specific heat capacity?</h3>
Specific heat capacity is the of heat to increase the temperature per unit mass.
The formula to calculate the specific heat is Q = mct.
The options are attached here:
- The temperature of a given sample is 1 %.
- The temperature that a given sample can withstand.
- The quantity of heat that is required to raise the sample's temperature by 1 °C1 °C (Kelvin).
- The quantity of heat that is required to raise 1 g of the sample by 1°C (Kelvin) at a constant pressure.
Thus, the correct option is 4. The quantity of heat that is required to raise 1 g of the sample by 1°C (Kelvin) at a constant pressure.
Learn more about specific heat capacity
brainly.com/question/1747943
#SPJ1
Answer:
300000Pa or 3×10^5 Pa
Explanation:
Since the problem involves only two parameters of volume and pressure, the formula for Boyle's law is suitably used.
Using Boyle's law
P1V1 = P2V2
P1 is the initial pressure = 1.5×10^5Pa
V1 is the initial volume = 0.08m3
P2 is the final pressure (required)
V2 is the final volume = 0.04 m3
From the formula, P2 = P1V1/V2
P2 = 1.5×10^5 × 0.08 ÷ 0.04
= 300000Pa or 3×10^5 Pa.
Answer:
54.1 % Ca, 43.2 % O, 2.7% H
Explanation:
Molecular formula for calcium hydroxide is Ca(OH)₂
As we don't have a mass of Ca(OH)₂ to find out the percentage composition, we consider that the question refers to 1 mol of compound.
1 mol of hydroxide weighs 74.08 g
1 mol of hydroxide has 1 mol of Ca, therefore 40.08 g are Ca
2 moles of O therefore 32g are O
2 moles of H therefore 2 g are H
Percentage composition is known as (Mass of element/Total mass) . 100
(40.08 / 74.08) . 100 = 54.1 %
(32 / 74.08) . 100 = 43.2 %
(2 / 74.08) . 100 = 2.7%
im a smart one
