Answer:
<em>The most constructive reflected wavelength would be 576.8 nm</em>
Explanation:
Given the thickness of oil t = 103 nm
refractive index n = 1.41
The refractive index is related to wavelength in a particular medium with the relationship below;
λ =λ / n ...............1
here λ is the wavelength in the medium (oil)
λ is the wavelength of light in vacuum
n is the refractive index
most constructively reflected wavelength will occur at the point of Most constructive interference, which is at;
2 t = λ / 2 .........1
Substituting the value that we have for λ in equation 1 into equation 2
2 t = (λ / n)/2
4t = λ / n
λ = 4nt
λ = 4 x 1.41 x 103 nm
λ = 576.8 nm
Therefore the most constructive reflected wavelength would be
576.8 nm
This is called: diffuse reflection
Answer:
The surface charge density on the plate,
Explanation:
It is given that,
Area of parallel plate capacitor,
Separation between the plates,
Electric field between the plates,
We need to find the surface charge density on the plates. The formula for electric field is given by :
Where
= surface charge density
Hence, this is the required solution.
Answer:
<em>a. 137.5 m</em>
<em>b. 550 m</em>
Explanation:
<u>Accelerated Motion
</u>
If an object is changing its velocity at a constant rate, it has a uniformly accelerated motion. When the object is moving in one fixed axis, then the sign of the acceleration is negative if the object is braking, and positive if the object is increasing its speed.
The initial speed vo, final speed vt, acceleration a, and distance traveled x are related by the formula
a. The Race Car A has an initial speed of 55 m/s and it's said to stop. We must find at what distance it goes to vf=0. This means that the above formula becomes
Solving for x
The acceleration is , negative because it's against the movement. Thus
b. If the car is going twice as fast (v0=110 m/s), then