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Goshia [24]
4 years ago
5

15. For waves moving at a constant speed, if the wavelength is doubled, the frequency is

Physics
1 answer:
faltersainse [42]4 years ago
5 0

Answer:

halved

.............

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4 years ago
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An AC generator has 80 rectangular loops on its armature. Each loop is 12 cm long and 8 cm wide. The armature rotates at 1200 rp
Sauron [17]

Answer: 28.96 V

Explanation:

Given

No of loops on the armature, N = 80

Length of the loop, l = 12 cm = 0.12 m

Width of the loop, b = 8 cm = 0.08 m

Speed of the armature, 1200 rpm

Magnetic field of the loop, B = 0.30 T

To solve this, we use the formula

V(max) = NBAω

Where,

A = area of loop

A = l*b = 0.12 * 0.08

A = 0.0096 m²

ω = 1200 rpm = 1200 * 2π/60 rad/s

ω = (1200 * 2 * 3.142) / 60

ω = 7540.8 / 60

ω = 125.68 rad/s

Substituting the values into the formula

V(max) = NBAω

V(max) = 80 * 0.30 * 0.0096 * 125.68

V(max) = 80 * 0.362

V(max) = 28.96 V

Therefore, the maximum output voltage of the generator would be 28.96 V

5 0
3 years ago
A rock is pulled back in a slingshot as shown in the diagram below. The elastic on the slingshot is displaced 0.2 meters from it
irakobra [83]

Answer:

id

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i don't know

4 0
3 years ago
In a carnival ride, passengers stand with their backs against the wall of a cylinder. The cylinder is set into rotation and the
Lerok [7]

Answer:

Minimum speed will  be equal to 2.213 m/sec

Explanation:

We have given radius of the r = 2 m

Coefficient of friction \mu =0.25

At minimum speed frictional force will be equal to centripetal force

So \mu mg=\frac{mv^2}{r}

\frac{v^2}{r}=\mu g

v=\sqrt{\mu rg}=\sqrt{0.25\times 2\times 9.8}=2.213m/sec

So the minimum speed will be equal to 2.213 m/sec

8 0
3 years ago
Overload refers to: A. Performing a weight-lifting exercise with the resistance (load) held overhead B. Using a demand (load) ab
andrey2020 [161]

Answer:

E. All of the answers are correct

Explanation:

Overload principle in fitness training is associated with a gradual development of an athlete's abilities by progressively increasing the athlete's load and training.

In order to do this, the athlete's limit must be surpassed albeit gradually at first then picked up later over time.

6 0
3 years ago
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