15. For waves moving at a constant speed, if the wavelength is doubled, the frequency is

(a) Calculate how much work is required to launch a spacecraft of mass m from the surface of the earth (mass mE, radius RE) and

notsponge [240]

Answer:

(a) The Work need to place spacecraft into low orbit is $Gmm_{E} /2R_{E}$

(b) Additional Work need to place the spacecraft far away from the earth is

$Gmm_{E} /2R_{E}$ .

(c) From part(a) and part(b) we observe the Both quantities are equal.

Explanation:

Explanation is in the following attachments

8 0

3 years ago

Any individual offspring produced through asexual reproduction is always:

IrinaK [193]

Answer:

genetically identical

Explanation:

in asexual reproduction it is genetically identicall

6 0

3 years ago

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WhT is marasmus my followers and following pls give answer in detail

Taya2010 [7]

Marasmus disease is caused due to vitamin deficiency. It usually occurs when a person's diet does not contain all the vitamins and nutrients that the body needs to function. It involves wasting of body tissues, mainly muscles, and subcutaneous fat and it resulted in severe restrictions in energy intake....

happy learning..

7 0

2 years ago

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8 points

Lunna [17]

The pilot might be correct (I think), because, if the gravity of the planet is strong, then the planet’s gravity will pull the spaceship into its orbit, so the engines don’t need to be on for the ship to get pushed toward the planet.

4 0

3 years ago

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Suppose that you lift four boxes individually, each at a constant velocity. The boxes have weights of 3.0 N, 4.0 N, 6.0 N, and 2

Alona [7]

Answer:

The vertical distance of weight 3.0 N = 4 m, vertical distance of weight 4.0 N = 3 m, vertical distance of weight 6.0 N = 2 m, vertical distance of weight 2.0 N = 6 m

Explanation:

Worked : work can be defined as the product of force and distance.

The S.I unit of work is Joules (J).

Mathematically it can be represented as,

W = F×d.................. Equation 1

d = W/F.............................. Equation 2

where W = work, F = force, d = distance.

Given: W = 12 J

(i) for the 3.0 N weight,

using equation 2

d = 12/3

d= 4 m.

(ii) for the 4.0 N weight,

d = 12/4

d = 3 m.

(iii) for the 6.0 N weight,

d = 12/6

d = 2 m.

(iv) for the 2.0 N weight,

d = 12/2

d = 6 m

Therefore vertical distance of weight 3.0 N = 4 m, vertical distance of weight 4.0 N = 3 m, vertical distance of weight 6.0 N = 2 m, vertical distance of weight 2.0 N = 6 m

8 0

3 years ago