15. For waves moving at a constant speed, if the wavelength is doubled, the frequency is

A balloon holds 50.0 mL of nitrogen at 25° C and a pressure of 736 mm Hg.

olganol [36]

Answer:

Explanation:

4 0

3 years ago

The top of a tower much like the leaning bell tower at Pisa, Italy, moves toward the south at an average rate of 1.4 mm/y. The t

Gemiola [76]

Answer:

$\omega=7.16*10^{-13}\frac{rad}{s}$

Explanation:

The angular speed is given by:

$\omega=\frac{v}{r}$

Here v is the linear speed and r is the radius of the circular motion. The height of the tower is equal to the radius of the circular motion of the top of the tower, since is rotating about its base. We need to convert the given linear speed to $\frac{m}{s}$ :

$1.4\frac{mm}{y}*\frac{10^{-3}m}{1mm}*\frac{1y}{3.154*10^7s}=4.44*10^{-11}\frac{m}{s}$

Now, we calculate the angular speed:

$\omega=\frac{4.44*10^{-11}\frac{m}{s}}{62m}\\\omega=7.16*10^{-13}\frac{rad}{s}$

8 0

4 years ago

All atoms of the same element must have the same number of

DIA [1.3K]

Since isotopes of any given element all contain the same number of protons,

3 0

4 years ago

Read 2 more answers

Ohm's Law for electrical circuits is stated VequalsRI, where V is a constant voltage, R is the resistance in ohms and I is the

Annette [7]

Answer:

The resistance interval is $R = 1.8 \pm 0.037$

Explanation:

From the question we are told that

The voltage is V = 9 V

The current is $I = 5 \pm 0.1$

The maximum current would be

$I_{max} = 5 + 0.1 = 5.1 \ A$

The minimum current would be

$I_{min} = 5 - 0.1 = 4.9 \ A$

The maximum resistance is

$R_max = \frac{V}{I_{min}}$

$R_max = \frac{9}{4.9}$

$R_max = 1.837 \Omega$

The minimum resistance is

$R_{min} = \frac{V}{I_{max}}$

$R_{min} = \frac{9}{5.1}$

$R_{min} = 1.765 \Omega$

and $R = \frac{9}{5} = 1.8 \Omega$

The interval R lies is

$R = 1.8 \pm 0.037$

4 0

3 years ago

A loop of current-carrying wire has a magnetic dipole moment of 5. 0 10–4 am2. if the dipole moment makes an angle of 57° with a

Digiron [165]

The potential energy will be 1.46*10^-4J.

To find the answer, we have to know about the torque acting on a current loop in a uniform magnetic field.

<h3>How to find the potential energy of the loop?</h3>

We have the expression for torque acting on a current loop in a uniform magnetic field as,

$\tau=MBsin\theta$

where; M is the magnetic dipole moment, B is the magnetic field , and theta is the angle between M and B.

As we know that, the torque is equal to force times the perpendicular distance. Thus, it is equivalent to the work done. This work is stored as the potential energy in the loop.
Thus, the potential energy will be,

$\tau=W=U=MBsin\theta=5*10^{-4}*0.35*sin57=1.46*10^{-4}J$

Thus, we can conclude that, the potential energy will be 1.46*10^-4J.

Learn more about the torque here:

brainly.com/question/27949876

#SPJ4

7 0

2 years ago