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Aleksandr-060686 [28]
3 years ago
6

At school, Susie received 4 stickers on Monday, 9 stickers on Tuesday, 14 stickers on Wednesday, and 24 stickers on Friday. If t

his pattern were followed all week, how many stickers did Susie receive on Thursday?
Mathematics
1 answer:
shtirl [24]3 years ago
3 0

Answer:

it goes up a by 5 everyday so it would be 19

Step-by-step explanation:

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A line passes through the points
masha68 [24]

Answer:

y=-2x+7

enter the point into point slope form to find the slope and then use one of the points in point slope form  and rearrange it to have y by itself

4 0
3 years ago
Please show work
cluponka [151]

Answer:

34.2 m

Step-by-step explanation:

We know that

Area of parallelogram = Base × Height

690.84 = B × 20.2

690.84/20.2 = B

34.2 = B

Hence,

Base of parallelogram is 34.2 m

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2 years ago
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Vanyuwa [196]
I think D too because that one is the only one that makes sense
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3 years ago
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Given: Circle k(O) Diameter <br><br>XY tangent WZ, XY = 10, and WZ = 12 .Find: YZ
PtichkaEL [24]

Answer:

<h2>Side YZ is 8 units long.</h2>

Step-by-step explanation:

We can deduct form the graph that segment WO is a radius of the circle and XY is its diameters.

By given, we know that XY = 10, which means WO=\frac{XY}{2}=\frac{10}{2}=5, by radius definition.

An important characteristic of tangents about circles is that the tangent is always is perpendicular to the radius, that means \angle OWZ = 90\°\\ and \triangle OWZ is a right triangle, that means we can use Pythagorean's Theorem to find the side YZ.

OZ^{2} =WZ^{2}+OW^{2}

Where OZ is the hypothenuse and WZ , OW are legs of the triangle.

Replacing all given values, we have

OZ^{2}=12^{2}+5^{2}\\OZ=\sqrt{144+25}=\sqrt{169}\\  OZ=13

However, by sum of segments, we have

OZ=OY+YZ, where OY=OW=5 and OZ=13

13=5+YZ\\YZ=13-5\\YZ=8

Therefore, side YZ is 8 units long.

3 0
3 years ago
Which statement about numbers is true?
Arturiano [62]

Answer: the answer is b or All rational numbers are Integers

Step-by-step explanation: brainlest please

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3 years ago
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