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Aleksandr-060686 [28]

2 years ago

6

At school, Susie received 4 stickers on Monday, 9 stickers on Tuesday, 14 stickers on Wednesday, and 24 stickers on Friday. If t

his pattern were followed all week, how many stickers did Susie receive on Thursday?

1 answer:

shtirl [24]2 years ago

3 0

Answer:

it goes up a by 5 everyday so it would be 19

Step-by-step explanation:

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Bill is putting his baseball cards in a binder. For the amount of baseball cards he has, he knows he can use either 5 on each pa

Alexandra [31]

45 because if he had any less, there would be left overs for either the 5 per page or 9 per page.

7 0

2 years ago

Read 2 more answers

Cosθ=−2√3 , where π≤θ≤3π2 .

Alex787 [66]

Answer:

$sin(\theta + \beta) = -\frac{\sqrt{7}}{5}-4\frac{\sqrt{2}}{15}$

Step-by-step explanation:

step 1

Find the $sin(\theta)$

we know that

Applying the trigonometric identity

$sin^2(\theta)+ cos^2(\theta)=1$

we have

$cos(\theta)=-\frac{\sqrt{2}}{3}$

substitute

$sin^2(\theta)+ (-\frac{\sqrt{2}}{3})^2=1$

$sin^2(\theta)+ \frac{2}{9}=1$

$sin^2(\theta)=1- \frac{2}{9}$

$sin^2(\theta)= \frac{7}{9}$

$sin(\theta)=\pm\frac{\sqrt{7}}{3}$

Remember that

π≤θ≤3π/2

so

Angle θ belong to the III Quadrant

That means ----> The sin(θ) is negative

$sin(\theta)=-\frac{\sqrt{7}}{3}$

step 2

Find the sec(β)

Applying the trigonometric identity

$tan^2(\beta)+1= sec^2(\beta)$

we have

$tan(\beta)=\frac{4}{3}$

substitute

$(\frac{4}{3})^2+1= sec^2(\beta)$

$\frac{16}{9}+1= sec^2(\beta)$

$sec^2(\beta)=\frac{25}{9}$

$sec(\beta)=\pm\frac{5}{3}$

we know

0≤β≤π/2 ----> II Quadrant

so

sec(β), sin(β) and cos(β) are positive

$sec(\beta)=\frac{5}{3}$

Remember that

$sec(\beta)=\frac{1}{cos(\beta)}$

therefore

$cos(\beta)=\frac{3}{5}$

step 3

Find the sin(β)

we know that

$tan(\beta)=\frac{sin(\beta)}{cos(\beta)}$

we have

$tan(\beta)=\frac{4}{3}$

$cos(\beta)=\frac{3}{5}$

substitute

$(4/3)=\frac{sin(\beta)}{(3/5)}$

therefore

$sin(\beta)=\frac{4}{5}$

step 4

Find sin(θ+β)

we know that

$sin(A + B) = sin A cos B + cos A sin B$

so

In this problem

$sin(\theta + \beta) = sin(\theta)cos(\beta)+ cos(\theta)sin (\beta)$

we have

$sin(\theta)=-\frac{\sqrt{7}}{3}$

$cos(\theta)=-\frac{\sqrt{2}}{3}$

$sin(\beta)=\frac{4}{5}$

$cos(\beta)=\frac{3}{5}$

substitute the given values in the formula

$sin(\theta + \beta) = (-\frac{\sqrt{7}}{3})(\frac{3}{5})+ (-\frac{\sqrt{2}}{3})(\frac{4}{5})$

$sin(\theta + \beta) = (-3\frac{\sqrt{7}}{15})+ (-4\frac{\sqrt{2}}{15})$

$sin(\theta + \beta) = -\frac{\sqrt{7}}{5}-4\frac{\sqrt{2}}{15}$

8 0

3 years ago

Which whole number is closest to 577.41 closest to?

Stella [2.4K]

578 bc 2 goes into 578 evenly

7 0

3 years ago

What is the total number of 0.3 pound meatballs Thomas can make with 8.1 pounds of meat?

SCORPION-xisa [38]

27

Divide

8.1 / 0.3

27

Hope this helps :)

7 0

3 years ago

Match the STATEMENTS with the reasons that are given for the following proof. Note that these reasons would be listed on the rig

dusya [7]

Answer:

Step-by-step explanation:

1. AB||DC and AB = CD Given

2. ∠1 = ∠4 If lines are parallel, then alternate interior

angles are equal.

3 .AC = AC Reflexive

4. ΔABC ≅ ΔCDA SAS

5. ∠2 = ∠3 CPCTE

4 0

2 years ago