X^2+43xy+590y^2 resolve into factors
1 answer:
Step-by-step explanation:
We have:
x - y = 43 , xy = 15
To find, the value of x^2+y^2x
2
+y
2
= ?
∴ x - y = 43
Squaring both sides, we get
(x - y)^2(x−y)
2
= 43^243
2
⇒ x^2+y^2x
2
+y
2
- 2xy = 1849
Using the algebraic identity,
(a - b)^2(a−b)
2
= a^2+b^2a
2
+b
2
- 2ab
⇒ x^2+y^2x
2
+y
2
= 1849 + 2xy
Put xy = 15, we get
x^2+y^2x
2
+y
2
= 1849 + 2(15)
⇒ x^2+y^2x
2
+y
2
= 1849 + 30
⇒ x^2+y^2x
2
+y
2
= 1879
∴ x^2+y^2x
2
+y
2
= 1879
I will send hint follow this hint then slove it .
thankyou
You might be interested in
37.8 because you multiply 3 by 12.6 i got 12.6 by dividing 63 by 5
The last six numbers are:
390, 395, 400, 405, 410, 415
Hope this helps☺
Hello,
It 's difficult to translate that in french.
l=16 ^(1/5)
w=2^(1/5)
Area=32^(1/5)=(2^5)^(1/5)=2 (in²)
Answer:
3 days
Step-by-step explanation:
The problem statement tells you that Kelly is there for 3 days.
