Answer:
Step-by-step explanation:
F(x)=(5 t^2+t )x to x+3
=5((x+3)^2-x^2)+(x+3-x)
=5(x^2+6x+9-x^2)+3
=5 (6x+9)+3
=30x+48
F'(x)=30
D.)1.7
it's positive and above the 1 point
I have wrote just answers
