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allochka39001 [22]
3 years ago
8

The vertex form of the equation of a parabola is y = 4(x - 2)2 - 1. What is the standard form of the equation?

Mathematics
2 answers:
Paladinen [302]3 years ago
8 0
Ok so your original equation was y=4(x-2)²-1
Therefore we need to expand the bracket to find the original equation.
To do this we need to find (x-2)²=x²-4x+4
Now we multiply this by 4 and subtract 1
4x²-16x+15 Therefore B is the answer
soldi70 [24.7K]3 years ago
4 0
Y = 4(x - 2)² - 1
y = 4(x² - 4x + 4) - 1 
y = 4x² - 16x + 16 - 1
y = 4x² - 16x + 15

<u>y = B(y)</u>
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A polynomial function can be written as (x + 1)(x + 4)(x – 7). What are the x-intercepts of the graph of this function?
attashe74 [19]

Answer:

fourth option

Step-by-step explanation:

Given

f(x) = (x + 1)(x + 4)(x - 7)

To find the x- intercepts let f(x) = 0, that is

(x + 1)(x + 4)(x - 7) = 0

Equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1

x + 4 = 0 ⇒ x = - 4

x - 7 = 0 ⇒ x = 7

x- intercepts are (- 1, 0 ), (- 4, 0 ), (7, 0 )

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3 years ago
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5 0
3 years ago
Which equation is equivalent to 2(3x-5)=5-2(1-x)
aniked [119]

Answer:

6(x-10)=5-2(1-x)

Step-by-step explanation:

I divided by 3 the parenthesis, and multiplied by 3 the first number, which makes an equivalent equation.

7 0
3 years ago
Write the letters of the expressions that are equivalent to the given expression.
Tresset [83]

Answer: A.) 10x + 15

Step-by-step explanation:

You would distribute (multiply) the 5 to the 2x which would then make it 10x and you would distribute (multiply) the 5 to the 3 which would then make it 15. Because the 5 is a positive number the sign stays the same.

Therefore, 10x + 15 is your answer.

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3 years ago
Simplify: 18q2−45q+25/9q2−25.
Svet_ta [14]

Answer:

\frac{(6q-5)}{(3q+5)}

Step-by-step explanation:

Given: \frac{18q^{2}-45q+25 }{9q^{2}-25 }

Factorizing the numerator and the denominator, we have:

18q^{2} - 45q + 25 = 18q^{2} - 30q - 15q + 25

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and

9q^{2} - 25 = (3q - 5)(3q + 5)

So that,

\frac{18q^{2}-45q+25 }{9q^{2}-25 } = \frac{(3q-5)(6q-5)}{(3q-5)(3q+5)}

                 = \frac{(6q-5)}{(3q+5)}

Therefore,

\frac{18q^{2}-45q+25 }{9q^{2}-25 } = \frac{(6q-5)}{(3q+5)}

5 0
3 years ago
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