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ycow [4]
3 years ago
6

teresa repartee un chocolate entre sus hermanos. ella le dio 1/3 a miguel y 1/4 a diego. que parte de chocolate repartido teresa

?
Mathematics
1 answer:
jekas [21]3 years ago
4 0

Answer:

Teresa tiene 1 chocolate.

Ella le da 1/3 del chocolate a Miguel, entonces ahora Teresa tendrá un chocolate menos un tercio de chocolate, es decir, ella tiene:

1 - 1/3 = 3/3 - 1/3 = 2/3 de un chocolate.

Ahora le da 1/4 a diego, entonces lo que le sobra va a ser:

2/3 - 1/4

recordar que tenemos que tener el mismo denominador en ambas fracciones, entonces podemos reescribir esto como:

(4/4)*(2/3) - (3/3)*(1/4)

(a cada fracción la multiplico y divido por el denominador de la otra)

8/12 - 3/12 = (8 - 3)/12 = 5/12

Es decir, Teresa finalmente tiene 5/12 del chocolate.

Entonces la parte de chocolate que repartió es lo que le falta, que se obtiene como:

1 - 5/12 = 12/12 - 5/12 = 7/12

Ella repartió 7/12 de su chocolate.

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<h3>Answer:   83.85%</h3>

This value is approximate.

==========================================================

Explanation:

Let's compute the z score for x = 40

z = (x-mu)/sigma

z = (40-47)/7

z = -1

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Repeat these steps for x = 68

z = (x-mu)/sigma

z = (68-47)/7

z = 3

This score is exactly three standard deviations above the mean.

Now refer to the Empirical Rule chart below. We'll add up the percentages that are between z = -1 and z = 3. This consists of the two pink regions (each 34%), the right blue region (13.5%) and the right green region (2.35%). These percentages are approximate.

34+34+13.5+2.35 = 83.85

<u>Roughly 83.85%</u> of the one-mile roadways have between 40 and 68 potholes.

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Answer:

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A mathematics teacher wanted to see the correlation between test scores and
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Answer:

The homework  grade, to the nearest integer, for a student with a test grade of 68 is 69.

Step-by-step explanation:

The general form of the linear regression equation is:

y=a+bx

Here,

<em>y</em> = dependent variable = test grade

<em>x</em> = independent variable = homework grade

<em>a</em> = intercept

<em>b</em> = slope

Compute the value of <em>a</em> and <em>b</em> as follows:

a=\frac{\sum Y\cdot \sum X^{2}-\sum X\cdot\sum XY}{n\cdot \sum X^{2}-(\sum X)^{2}}\\\\=\frac{(592\times 44909)-(591\times45227)}{(8\times44909)-(591)^{2}}\\\\=-14.316                b=\frac{n\cdot \sum XY-\sum X\cdot\sum Y}{n\cdot \sum X^{2}-(\sum X)^{2}}\\\\=\frac{(8\times 45227)-(591\592)}{(8\times44909)-(591)^{2}}\\\\=1.195

The linear regression equation that represents the set of data is:

y=-14.316+1.195x

Compute the value of <em>x</em> for <em>y</em> = 68 as follows:

y=-14.316+1.195x

68=-14.316+1.195x\\1.195x=68+14.316\\1.195x=82.316\\x=68.884\\x\approx 69

Thus, the homework  grade, to the nearest integer, for a student with a test grade of 68 is 69.

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Answer:

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Step-by-step explanation:

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