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ycow [4]
3 years ago
6

teresa repartee un chocolate entre sus hermanos. ella le dio 1/3 a miguel y 1/4 a diego. que parte de chocolate repartido teresa

?
Mathematics
1 answer:
jekas [21]3 years ago
4 0

Answer:

Teresa tiene 1 chocolate.

Ella le da 1/3 del chocolate a Miguel, entonces ahora Teresa tendrá un chocolate menos un tercio de chocolate, es decir, ella tiene:

1 - 1/3 = 3/3 - 1/3 = 2/3 de un chocolate.

Ahora le da 1/4 a diego, entonces lo que le sobra va a ser:

2/3 - 1/4

recordar que tenemos que tener el mismo denominador en ambas fracciones, entonces podemos reescribir esto como:

(4/4)*(2/3) - (3/3)*(1/4)

(a cada fracción la multiplico y divido por el denominador de la otra)

8/12 - 3/12 = (8 - 3)/12 = 5/12

Es decir, Teresa finalmente tiene 5/12 del chocolate.

Entonces la parte de chocolate que repartió es lo que le falta, que se obtiene como:

1 - 5/12 = 12/12 - 5/12 = 7/12

Ella repartió 7/12 de su chocolate.

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Step-by-step explanation:

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2 years ago
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7 0
2 years ago
Margie has 5 times as many nickels as quarters. She has a total of $2.00.
stich3 [128]

Answer:

<u>Part A: </u>

<u>n = 5q (1st equation)</u>

<u>0.05n + 0.25q = 2 (2nd equation)</u>

<u>Part B:</u>

<u>q = 4 ⇒ n = 5 * 4 = 20</u>

<u>Part C:</u>

<u>Margie has 20 nickels and 4 quarters, for a total of $ 2.00</u>

Step-by-step explanation:

Let's recall that a nickel has a value of $ 0.05 and a quarter a value of $ 0.25.

Let n represent the number of nickels and q represent the number of quarters.

Part A:

Write a system of equations to represent the situation.

n = 5q (1st equation)

n * 0.05 + q * 0.25 = 2

0.05n + 0.25q = 2 (2nd equation)

Part B:

Replacing n in the 2nd equation to solve for q:

0.05n + 0.25q = 2

0.05 * 5q + 0.25q = 2

0.25q + 0.25q = 2

0.5q = 2

q = 2/0.5

<u>q = 4 ⇒ n = 5 * 4 = 20</u>

<u>Part C:</u>

<u>Margie has 20 nickels and 4 quarters, for a total of $ 2.00</u>

3 0
3 years ago
I’ll give brainliest:) help thanks
liubo4ka [24]

Answer:

A

hope this helps

have a good day :)

Step-by-step explanation:

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