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const2013 [10]
3 years ago
5

write an expression with (-1) as its base that will produce a positive product, and explain why your answer is valid.

Mathematics
2 answers:
Viktor [21]3 years ago
5 0

The expression with (-1) as its base , having x as it's exponent will be written as

\rightarrow (-1)^x

→The function will yield a Positive product if

 x=Even Integer=E

\rightarrow (-1)^{E}=1

→And ,Negative Product

x=Odd Integer=O

\rightarrow (-1)^{O}=-1

Simora [160]3 years ago
3 0
........................................... i dont know, i dont remember doing this
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Mademuasel [1]

Answer:

It would be y=12x

Step-by-step explanation:

I think

8 0
2 years ago
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what is the simplified form of the following expression? Assume X 0 and y 0. 2(^4 sqrt 16 x) -2(^4 sqrt 2y )+3 (^4 sqrt 81x ) -4
eduard

For this case we have the following expression:

2(\sqrt[4]{16x})-2(\sqrt[4]{2y})+3(\sqrt[4]{81x})-4(\sqrt[4]{32y})

Rewriting the numbers within the roots we have:

2(\sqrt[4]{2*2*2*2x})-2(\sqrt[4]{2y})+3(\sqrt[4]{3*3*3*3x})-4(\sqrt[4]{2*2*2*2*2y})

Then, by properties of powers we have:

2(\sqrt[4]{2^4x})-2(\sqrt[4]{2y})+3(\sqrt[4]{3^4x})-4(\sqrt[4]{2^42y})

Then, by radical properties we have:

2(2\sqrt[4]{x})-2(\sqrt[4]{2y})+3(3\sqrt[4]{x})-4(2\sqrt[4]{2y})

Rewriting the expression we have:

4\sqrt[4]{x}-2\sqrt[4]{2y}+9\sqrt[4]{x}-8\sqrt[4]{2y}

Finally, adding similar terms we have:

(4+9)\sqrt[4]{x}-(2+8)\sqrt[4]{2y}

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Answer:

The simplified form of the expression is:

13\sqrt[4]{x}-10\sqrt[4]{2y}

7 0
3 years ago
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What number would complete the pattern? 107 98 90 83 77_68 65
Leviafan [203]
Going from 107 to 98 is (minus 9)
going from 98 to 90 is (minus 8)
going from 90 to 83 is (minus 7)
going from 83 to 77 is (minus 6)

following this pattern, the number after 77
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7 0
3 years ago
which properties are present in a table that represents an exponential function in the form y=b^x when b>1​
vladimir1956 [14]

Answer:

The function has the property of exponential growth function.

Step-by-step explanation:

The exponential function is given by y = b^{x}, where b > 1.

Now, for x = 0, we get y = 1,

For x = 1, we get y = b

For, x = 2, we get y = b²

And so on.

Now, as b > 1, so, b² > b > 1 and the values of y are increasing as the value of x increases.

Therefore, the function has the property of exponential growth function.

3 0
4 years ago
Which statements about experimental probability are true? Select three options. Experimental probability has the total number of
erma4kov [3.2K]

Answer:

C D E or 345

Step-by-step explanation:

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