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astraxan [27]
3 years ago
6

In 2010, Car A was the highest mileage car available in a country. It's estimated highway mileage was 4 miles per gallon more th

an car B . if the two cars could travel a total of 90 miles on a gallon of gasoline, find the mileage of each car.​
Mathematics
1 answer:
Oksana_A [137]3 years ago
3 0

Answer:

Car B = 43 miles per gallon

Car A = 43+4=47 miles per gallons

Step-by-step explanation:

Let the mileage of Car B be x miles per gallon

Hence the mileage of Car A will be x+4 miles per gallon

Distance traveled by each car in 1 gallon

Car A = x+4

Car B = x

Total Distance covered by both car in 1 gallon = x+(x+4) which is given as 90 miles

Hence x+(x+4)=90

2x+4=90

2x=86

dividing both sides by 2 we get

x=43

Mileage of Car B = 43 miles per gallon

Mileage of Car A = 43+4=47 miles per gallons

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The diagram below shows an Isosceles triangle. Label the base angles and the vertex
Dmitry [639]

The base angles of an isosceles triangle are equal

The base angles are 15 degrees, while the vertex angle is 150 degrees

The base angles are given as:

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So, we have:

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Collect like terms

\mathbf{6a -a =3 + 12}

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Substitute 3 for a in Base = (6a- 3),

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The vertex angle is calculated using:

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So, we have:

\mathbf{Vertex=180 -2 \times 15}

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Read more about isosceles triangles at:

brainly.com/question/25739654

6 0
2 years ago
(b) Let X(s) and Y(s) denote the Laplace transforms of x(t) and y(t), respectively. Find H(s) = Y(s)/X(s). Assume zero initial c
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lorasvet [3.4K]

Answer:

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hope this helps!

7 0
3 years ago
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