The base angles of an isosceles triangle are equal
The base angles are 15 degrees, while the vertex angle is 150 degrees
The base angles are given as:
Base = (6a- 3) and (a + 12)
So, we have:

Collect like terms


Divide both sides by 5

Substitute 3 for a in Base = (6a- 3),



So, the base angle is 15 degrees.
The vertex angle is calculated using:

So, we have:


Hence, the vertex angle is 150 degrees
Read more about isosceles triangles at:
brainly.com/question/25739654
Answer:
H(s)=(∫_(t=o)^∞▒〖x(t)e^(-st) dt〗)/(∫_(t=o)^∞▒〖y(t) e^(-st) dt〗)
Step-by-step explanation:
L{f(t)}=F(s)=∫_(t=0)^∞▒〖f(t)e^(-st) dt〗
Answer:
y>-3 y>-7
Step-by-step explanation:
-(y+5)>2
y<-7
Answer:
maybe since the rhombus is divided into triangles it'll be easier. x = 8
Step-by-step explanation:
the total degrees in a triangle would be 180 and the inner little angles would be 90 degrees so you would solve for (7x - 1) + (4x + 3) + 90 = 180 so 11x + 2 = 90 so 11x = 88 so x = 8
hope this helps!