These <span>large leaves of ferns that show multiple venation are called fronds.</span>
Within a gymnosperm megasporangium, the following developmental sequences that are correct, assuming fertilization occurs is: megaspore, female gametophyte, egg cell, sporophyte embryo. The last Option (Option D) is correct.
In gymnosperm megasporangium, the meiotic division produces four haploid megaspores from a single cell, three of which generally degenerate. The female gametophyte is formed by mitosis from the surviving megaspore.
Prior to fertilization, the male mature gametophyte needs to be transferred to the female gametophyte for fertilization to take place.
When the nuclei of the sperm encounter the nucleus of the egg cell in gymnosperms, it fuses with the egg nucleus to produce a diploid zygote.
Mitosis occurs in the fertilized egg to initiate the growth of a new sporophyte generation (the multicellular embryo of the seed.)
Therefore, we can conclude that we've understood the mechanism of developmental sequence in the gymnosperm megasporangium.
Learn more about the gymnosperm here:
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Spermatogenesis is the process by which haploid spermatozoa develop from germ cells in the seminiferous tubules of the testis. This process starts with the mitotic division of the stem cells located close to the basement membrane of the tubules.
4 cells would be created after meiosis and each cell would have 7 chromosomes.
<h3>Meiosis</h3>
Meiosis is the division of non-vegetative cells. It is a reductional division during which the ploidy level of the parent cell is halved in the daughter cells.
Thus, a cell with 2n = 14 that undergoes meiosis will produce daughter cells with n = 7.
Usually, 4 daughter cells are produced at the end of meiosis.
More on meiosis can be found here: brainly.com/question/7002092?referrer=searchResults
