What's the answer to y = 6 ; x = 2 and please show me how to do it.
1 answer:
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Hello,
First you have order all the number least to the greater. That gives 30, 75, 80, 85, 85, 95, 95, 100, 100, 110.
Afterwards you have to find the median. Why ?
I will explain you. It's because the median is robust. In fact, it can't be influenced by extreme values (example : 110) but the mean yes. So the mean won't be accurate.
"Then why don't you choose the mode ? " you will ask me. That's because the mode takes the number which appears most often in a set of numbers. It couldn't be accurate at all. It will be useless for this set of numbers.
Furthermore, here there are 3 numbers which appears the most ( 2 times for each) : $85, $95 and $100. Which one will you take ?
Therefore the median is the most suitable and the most accurate to know the center because it is robust.
Now, let's find the median :
There are 10 values, so the median will be the average of the 5th and 6th values.
5th value = 85
6th value = 95
Therefore the median is 90.
Hope this helps !
Photon
First you have order all the number least to the greater. That gives 30, 75, 80, 85, 85, 95, 95, 100, 100, 110.
Afterwards you have to find the median. Why ?
I will explain you. It's because the median is robust. In fact, it can't be influenced by extreme values (example : 110) but the mean yes. So the mean won't be accurate.
"Then why don't you choose the mode ? " you will ask me. That's because the mode takes the number which appears most often in a set of numbers. It couldn't be accurate at all. It will be useless for this set of numbers.
Furthermore, here there are 3 numbers which appears the most ( 2 times for each) : $85, $95 and $100. Which one will you take ?
Therefore the median is the most suitable and the most accurate to know the center because it is robust.
Now, let's find the median :
There are 10 values, so the median will be the average of the 5th and 6th values.
5th value = 85
6th value = 95
Therefore the median is 90.
Hope this helps !
Photon
Given:
Slips of paper numbered 1 to 15 are placed in a box.
To find:
The probability that the number picked is either a multiple of 5 or an odd number.
Solution:
We have,
Total outcomes = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15
No. of total outcomes = 15
Multiple of 5 are 5, 10, 15.
Odd numbers are 1, 3, 5, 7, 9, 11, 13, 15.
Number that are either a multiple of 5 or an odd number are 1, 3, 5, 7, 9, 10, 11, 13, 15.
No. of favorable outcomes = 9
We know that,
Therefore, the probability that the number picked is either a multiple of 5 or an odd number is 0.6.
Answer:
Step-by-step explanation:
for two lines to be parallel they MUST have the same slope but have different Y intercepts ( Y axis crossing values)
parallel lines will never intersect each other
first I use a graphing calcuator to solve the problem
I like to use y intercept form better, but you don't have use it
I will try to solve it directly without going through the y intercept equation
x + 5y = 10 in y intercept form y = mx + b is
5y = -x + 10 divide both sides by 5
y = -x/5 + 10/5
y = -x/5 + 2
Now I need to find a parallel line that passes through the x =1 and y = 3 point recall this line will have the same slope = m = -1/5
and a different Y axis crossing point 'b' that we don't know
y = -x/5 + b y = 3 when x = 1 so slove for 'b'
3 = -1/5 + b
3 = -0.2 + b add -0.2 to both sides
3.2 = b
y = -x/5 + 3.2 this is answer in y intercept form
if you multiply both sides by 5
5y = -x + 16 add x to both sides
x + 5y = 16 answer in standard form
THE EASIER WAY TO SOLVE THE PROBLEM IS ......
x + 5y = 10 find a line parallel that passes through x = 1, y = 3
x + 5y = Z Z is an unknown value plug in x and y and solve for Z
1 + 5(3) = Z
Z = 16 so the parallel line in standard form is
x + 5y = 16
same as before, my y intercept method was correct, but not worth the effort
