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2 years ago

Solve for x: x³=23 Choose all that apply: ∛23 3 1 23/3

Mathematics

2 answers:

Hatshy [7]2 years ago

8 0

Answer:

A and D. $\sqrt[3]{23}$ and 23/3.

Step-by-step explanation:

That exponent on the x works for A, and division also works for D.

hope this helped.

plz let me know if I am wrong.

rosijanka [135]2 years ago

6 0

Your answer is A. I have attached a photo of an explanation

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Which of the following is an integer?<br> 10.5<br> -9<br> XandY<br> 1/2

elena-14-01-66 [18.8K]

Answer:

-9

Step-by-step explanation:

an integer is a whole number!

4 0

3 years ago

Read 2 more answers

Can someone pls help me with this?

lara [203]

Answer:

14 is A

15 is B

Step-by-step explanation:

14 . the answer is a because first off the slope is negative so we can immediately eliminate B and D second of all the slope is 1/2 so we can eliminate D and get that the answer has to be a

15. answer is B for this one because first of all the slope is negative so we can immediately eliminate A and c and second of all the y-intercept would be 120 because 90 is what x=1 so we would have to add 30 to get what y would equal when x=0 if that makes sense

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3 years ago

The probability that a customer of a network operator has a problem about you needing technical staff's help in a month is 0.01.

snow_tiger [21]

Answer:

(a) average calls = 5

(b) probability that there is exactly one call in 6 consecutive monts = 0.038

Step-by-step explanation:

Let event of a customer requiring help in a particular month = H

and event of a customer not requiring help in a particular month = ~H

Given

p= 0.01, therefore

Number of households, n = 500.

Binomial distribution:

x = number of households requiring help in a particular month

P(x,n,p) = C(x,n)*p^x*(1-p)^(n-x)

where

C(x,n) = n!/(x!(n-x)!) is the the number of combinations of x objects out of n

(a) Average number of households requiring help = np = 500*0.01 = 5

(b)

Probability that there are no calls requiring help in a particular month

P(0), q= C(0,n)*p^0(1-p)^(n-0)

= 1*1*0.99^500

= 0.006570483

Applying binomial probability over six months,

q = 0.006570483

n = 6

x = 1

P(x,n,q)

= C(x,n)*q^x*(1-q)^(n-x)

= 6!/(1!*5!) * 0.006570483^1 * (1-0.006570483)^5

= 0.038145

Therefore the probability that in 6 consecutive months there is exactly one month that no customer has called for help = 0.038

3 0

3 years ago

University degree requirements typically are different for Bachelor of Science degrees and Bachelor of Arts degrees. Some studen

ira [324]

Answer:

A. 0.1

B. 0.8

C. 0.5

Step-by-step explanation:

Given:

P(Science) = 0.3

P(Arts) = 0.6

P(none) = 0.2

From the above, it is understood that the events are independently events; meaning that the probability that a students gets a Bachelor of Science degree does not affect the probability of the same student getting a Bachelor of Arts degree.

A. The probability that a student gets a Bachelor of Science and Bachelor of Arts degree

Let P(Arts and Science) = the probability that a student gets a Bachelor of Arts degree and Bachelor of Science degree

For independent events,

P(A) + P(B) - P(A and B) + P(none)= 1

If we translate the above formula to suit our needs, we have something like this

P(Science) + P(Arts) - P(Arts and Science) + P(none) = 1

P(Arts) + P(Science) - P(Arts and Science) + P(none) = 1

From this, we have

0.3 + 0.6 - P(Arts and Science) + 0.2 = 1

1.1 - P(Arts and Science) = 1

-P(Arts and Science) = 1 - 1.1

-P(Arts and Science) = -0.1

P(Arts and Science) = 0.1

B. The probability that a student gets a Bachelor of Science or Bachelor of Arts degree

For independent events

P(A or B) = P(A) + P(B) - P(A and B)

So, P(Arts or Science) = P(Arts) + P(Science) - P(Arts and Science)

P(Arts or Science) = 0.3 + 0.6 - 0.1

P(Arts or Science) = 0.8

C. The probability that a student gets only Bachelor of Arts

P(A only) = P(A) - P(A and B)

P(Arts) = P(Arts) - P(Arts and Science)

P(Arts) = 0.6 - 0.1

P(Arts) = 0.5

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3 years ago

To which set of numbers does the number belong?

Maslowich

Integers are whole numbers that can be negative or positive. Irrational numbers are numbers with repeating ends while natural numbers are positive whole numbers only. rational numbers are fractions. hence the answer to this problem is D.

6 0

3 years ago