Question

ula1" title=" \sqrt{2} \div 2 + 2 \div \sqrt{2 } " alt=" \sqrt{2} \div 2 + 2 \div \sqrt{2 } " align="absmiddle" class="latex-formula">
What does it equal to?? ​

Answer 1

Answer:

$\frac{3\sqrt{2} }{2}$

Step-by-step explanation:

Given

$\frac{\sqrt{2} }{2}$ + $\frac{2}{\sqrt{2} }$ ← rationalise the denominator by multiplying by $\frac{\sqrt{2} }{\sqrt{2} }$

= $\frac{\sqrt{2} }{2}$ + ( $\frac{2}{\sqrt{2} }$ × $\frac{\sqrt{2} }{\sqrt{2} }$ )

= $\frac{\sqrt{2} }{2}$ + $\frac{2\sqrt{2} }{2}$

= $\frac{3\sqrt{2} }{2}$