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lorasvet [3.4K]
2 years ago
14

Determine the solution(s) to the system given the pair of tables. Fill in the blanks with your answers.

Mathematics
1 answer:
irinina [24]2 years ago
4 0

<u>Given</u>:

The values of the functions f(x) and g(x) in a table.

We need to determine the solutions of the functions f(x) and g(x)

<u>Solutions:</u>

The solution of the function is the point at which both the functions have the same value at that point.

Thus, from the table of f(x) and g(x), it is obvious that both the functions have the same value -4 when x = -1

Thus, the solution is (-1,-4)

Also, from the table, the functions f(x) and g(x) have the same value 6 when x = 4.

Thus, the solution is (4,6)

Therefore, the solutions of the functions are (-1,-4) and (4,6)

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How many units long is a segment whose endpoints are (2,3) and (7,15)?
Ahat [919]

Answer:

13 units

Step-by-step explanation:

Distance formula: d = \sqrt{(x2-x1)^2 + (y2-y1)^2}

Simply plug in your variables

d = \sqrt{(7-2)^2 + (15-3)^2}

d = \sqrt{5^2 + 12^2}

d = \sqrt{25 + 144}

d = \sqrt{169}

d = 13

5 0
3 years ago
a right triangle has a non hypotenuse side length of 45" and the hypotenuse measures 53". What is the length of the other non-hy
Ede4ka [16]

Answer:

28"

Step-by-step explanation:

the length of the other non-hypotenuse side =

√(53² - 45²) =√(2809-2025) =√784 = 28"

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2 years ago
Read 2 more answers
Obtain the general solution to the equation. (x^2+10) + xy = 4x=0 The general solution is y(x) = ignoring lost solutions, if any
alukav5142 [94]

Answer:

y(x)=4+\frac{C}{\sqrt{x^2+10}}

Step-by-step explanation:

We are given that a differential equation

(x^2+10)y'+xy-4x=0

We have to find the general solution of given differential equation

y'+\frac{x}{x^2+10}y-\frac{4x}{x^2+10}=0

y'+\frac{x}{x^2+10}y=4\frac{x}{x^2+10}

Compare with

y'+P(x) y=Q(x)

We get

P(x)=\frac{x}{x^2+10}

Q(x)=\frac{4x}{x^2+10}

I.F=e^{\int\frac{x}{x^2+10} dx}=e^{\frac{1}{2}ln(x^2+10)}

e^{ln\sqrt(x^2+10)}=\sqrt{x^2+10}

y\cdot \sqrt{x^2+10}=\int \frac{4x}{x^2+10}\times \sqrt{x^2+10} dx+C

y\cdot \sqrt{x^2+10}=\int \frac{4x}{\sqrt{x^2+10}}+C

y\cdot \sqrt{x^2+10}=4\sqrt{x^2+10}+C

y(x)=4+\frac{C}{\sqrt{x^2+10}}

6 0
3 years ago
The sum of seven angles of an octagon is 132 degrees each. Find the measure of the eighth angle.
Sauron [17]

the sum of the angles in an ngon (a polygon with n sides) is (n-2)*180

so an octagon has 8 sides and has a sum total of (8-2)*180=1080 degrees

if each of 7 angles is 132, then 1080=?+7*132

1080=?+924

156=?

the 8th angle is 156 degrees

6 0
3 years ago
Sharon rented a car for a base price of $200 and has to pay $13 for each day she drives. If her total bill is $252, how many day
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three thousand two handrend and seventy six

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2 years ago
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