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3 years ago

Please help I need by today !!

1 answer:

3 0

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If the open circuit voltage of a circuit containing ideal sources and resistors is measured at 8 , while the current through the

solmaris [256]

Answer:

The power absorbed by the 60 ohm resistor is 1.064 W

Explanation:

When there's no load connected to the source (open circuit) its voltage output is ideal, since there won't be any voltage drop across it's internal resistance. When there's a shor circuit, the only load is the internal resistance of the source, so we can use Ohm's law to compute the internal resistance, as shown bellow:

Rinternal = Vopenload/Ishortcircuit

Rinternal = 8/200 = 0.04 Ohm

When we connect a load to this source, the total load we'll be the external resistance plus the internal resistance. We can now compute the curent flow when there's a 60 Ohm resistance connected to the terminals of the source by using Ohm's law again:

I = Vsource/(Rexternal + Rinternal)

I = 8/(60 + 0.04) = 8/(60.04) = 0.1332 A

The absorbed power is the product of the voltage across the terminals of the resistor and the current that goes through it. The current is the one we calculated above and the voltage across it's terminals is given by I*R, so the power output is:

P = I*Vresistor

P = I*(I*R)

P = R*I^2 = 60*(0.1332)^2 = 1.064 W

8 0

3 years ago

Read 2 more answers

A liquid level control system linearly converts a displacement of 2-3 meters into a 4-20 mA control signal. A relay closes at 12

yaroslaw [1]

Answer:

a)H = 0.0625 I + 1.75

b)Neutral zone=0.125 m

Explanation:

Given that

$H_{min}= 2 m$

$H_{max}= 3 m$

$I_{min}=4\ mA$

$H_{max}= 20\ mA$

The relationship between current and displacement is given as follows

H= K I + H0

Now by putting the values

3 = K x 20 + H0

2 = K x 4 + H0

Therefore

1 = 16 K

K=0.0625

H0=2- 0.0625 x 4

H0=1.75

The relationship is given as follows

H = 0.0625 I + 1.75

Now ,

$I_H=12\ mA$

$H_H=0.0625\times 12+1.75$

$H_H=2.5$

$I_L=10\ mA$

$H_L=0.0625\times 10+1.75$

$H_L=2.375$

Neutral zone is given as follows

Neutral zone=2.5-2.375

Neutral zone=0.125 m

3 0

4 years ago

Calculate the angle of banking on a bend of 100m radius so that vehicles can travel round the bend at 50km/hr without side thrus

saw5 [17]

Answer:

11.125°

Explanation:

Given:

Radius of bend, R = 100 m

Speed around the bend = 50 Km/hr = $\frac{5}{18}\times50$ = 13.89 m/s

Now,

We have the relation

$\tan\theta=\frac{v^2}{gR}$

where,

θ = angle of banking

g is the acceleration due to gravity

on substituting the respective values, we get

$\tan\theta=\frac{13.89^2}{9.81\times100}$

$\tan\theta=0.1966$

θ = 11.125°

3 0

3 years ago

You have a piece of 1045 steel 80 cm long and 30 cm wide and 15cm high. In this piece it is desired to make a groove along the 8

tino4ka555 [31]

Answer:

0.65 m/min

Explanation:

The volume of material to be removed is

80*8*10 = 650 cm^3

The tool has a diameter of 4 mm and a maximum axial cutting capacity of 50 mm, so its cross section normal to advance is

0.4*5 = 2 cm^2

If the groove have to be made in T = 5 minutes the advance speed would be

V/(S * T)

650/(2 * 5) = 65 cm/min = 0.65 m/min

4 0

3 years ago

You installed a new 40 gallon water heater with a 54,000 BTUh burner. The underground water temperature coming into the house is

allochka39001 [22]

Answer:

For most uses you'll want your water heated to 120 F(49 C) In this example you'd need a demand water heater that produces a temperature rise and it will take about 2 hours

7 0

3 years ago