Which of the following is not a relationship set between elements in a sketch
1 answer:
You might be interested in
Answer:
<em>a) 50 J/kg</em>
<em>b) 721 67 KW</em>
<em></em>
Explanation:
The velocity of the wind v = 10 m/s
diameter of the blades d = 70 m
efficiency of the turbine η = 30%
density of air ρ = 1.25 kg/m^3
The area of the blade A =
A = = 3848.95 m^2
The mechanical energy air per unit mass is gives as
e = =
= <em>50 J/kg</em>
<em></em>
Theoretical Power of the turbine P = ρAve
where
ρ is the density of air
A is the area of the blade
v is the velocity of the wind
e is the energy per unit mass
substituting values, we have
P = 1.25 x 3848.95 x 10 x 50 = 2405593.75 W
Actual power = ηP
where η is the efficiency of the turbine
P is the theoretical power of the turbine
Actual power = 0.3 x 2405593.75 = 721678.1 W
==> <em>721 67 KW</em>
Answer:
Reflection Coefficient =
SWR=3.65
Position of
position of
Explanation:
To determine the above answers, let outline the useful formulas
refection coefficient .
where terminal impednce = (30-i50)Ω
characteristics impedance= 50Ω
Secondly, the Standing Wave Ratio,
Now let us substitute values and solve,
a.
multiplying the numerator and denominator by the conjugate of the denominator. we have
by carrying out careful operation, we arrived at
To express in polar form i.e
to get the angle
alpha=
hence the Reflection Coefficient,<em>p</em> =
b. we now determine the Standing Wave Ratio,
c. to determine the position of the maximum voltage nearest to the load,
we use the equation
were is the wavelength of 8cm
lets convert α to rad by multiplying by π/180
.
d. also were we have minimum voltage,there the maximum current will exist, to find this position nearest to the load
.
since the voltage minimum occure at 1.11cm. we can conclude that the current maximum also occur at this point i.e 1.11cm
Answer:
Explanation:
Given that:
The direction of the applied tensile stress =[001]
direction of the slip plane = [01]
normal to the slip plane = [111]
Now, the first thing to do is to calculate the angle between the tensile stress and the slip by using the formula:
where;
= directional indices for tensile stress
= slip direction
replacing their values;
i.e = 0 ,
= 0
= 1 &
= -1 ,
= 0 ,
= 1
Also, to find the angle between the stress [001] & normal slip plane [111]
Then;
replacing their values;
i.e = 0 ,
= 0
= 1 &
= 1 ,
= 1 ,
= 1
However, the critical resolved SS(shear stress) can be computed using the formula:
where;
applied tensile stress 13.9 MPa
∴