Answer: A 1 MHz
Explanation:
10Khs equals to 10,000Hz/10Khz/0.01Mhz/0.00001Ghz
i believe the correct answer is c but i’m sorry if i’m not correct
Answer: Fracture will not occur since Kc (32.2 MPa√m) ∠ KIc (35 MPa√m).
Explanation:
in this question we are asked to determine if an aircraft will fracture for a given fracture toughness.
let us begin,
from the question we have that;
stress = 325 MPa
fracture toughness (KIc) = 35 MPa√m
the max internal crack length = 1.0 m
using the formula;
Y = KIc/σ√(πα) ---------------(1)
solving for Y we have;
Y = 35 (MPa√m) / 250 (MPa) √(π × 2×10⁻3/2m)
Y = 2.50
so to calculate the fracture roughness;
Kc = Y × σ√(πα) = 2.5 × 3.25√(π × 1×10⁻³/2) = 32.2 MPa√m
Kc = 32.2 MPa√m
From our results we can say that fracture will not occur since Kc (32.2 MPa√m) is less than KIc (35 MPa√m) of the material.
cheers i hope this helps!!!!
Answer:
Re=100,000⇒Q=275.25 
Re=500,000⇒Q=1,757.77
Re=1,000,000⇒Q=3060.36 
Explanation:
Given:
For air
=25°C ,V=8 m/s
For surface
=179°C
L=2.75 m ,b=3 m
We know that for flat plate
⇒Laminar flow
⇒Turbulent flow
<u> Take Re=100,000:</u>
So this is case of laminar flow

From standard air property table at 25°C
Pr= is 0.71 ,K=26.24
So 
Nu=187.32 (
)
187.32=
⇒h=1.78
heat transfer rate =h
=275.25 
<u> Take Re=500,000:</u>
So this is case of turbulent flow


Nu=1196.18 ⇒h=11.14 
heat transfer rate =h
=11.14(179-25)
= 1,757.77
<u> Take Re=1,000,000:</u>
So this is case of turbulent flow


Nu=2082.6 ⇒h=19.87 
heat transfer rate =h
=19.87(179-25)
= 3060.36 