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Crazy boy [7]
3 years ago
14

A. Paleozoic

Engineering
2 answers:
Mashutka [201]3 years ago
7 0
The answer to your question is Cenozoic
garri49 [273]3 years ago
5 0
Pretty sure it’s Cenozoic
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Silicon chips are used primarily in ?
VMariaS [17]

Answer:

4th generation computers

5 0
2 years ago
The A/C compressor will not engage when the A/C is turned on. The static refrigerant pressure is 75 psi and the outside temperat
VikaD [51]

In the case above,  poor connection at the pressure cycling switch  and also a faulty A/C clutch coil could be the cause.

<h3>What is likely the reason when an A/C compressor will not engage if A/C is turned on?</h3>

The cause that hinders the A/C Compressor from engaging are:

  • Due to low pressure lockout.
  • Due to a poor ground
  • Due to bad clutch coil.
  • Dur to an opening in the wire that links to the clutch coil.
  • Due to a blown fuse.

Note that the pressure switches is known to be one that control the on/off function of any kind of AC compressor and as such, if there is switch failure, it can hinder the AC compressor from functioning at all.

Therefore, technician A and B are correct.

Learn more about refrigerant pressure from

brainly.com/question/10054719

#SPJ1

3 0
2 years ago
Which explanation best summarizes what went wrong during Paul’s cost analysis?
Valentin [98]

Answer:

wut is it

Explanation:

4 0
2 years ago
A hydraulic cylinder is to be used to move a workpiece in a manufacturing operation through a distance of 50 mm in 10 s. A force
svetlana [45]

Answer:

The answer to this question is 1273885.3 ∅

Explanation:

<em>The first step is to determine the required  hydraulic flow rate liquid if working pressure and  if a cylinder with a piston diameter of 100 mm is available.</em>

<em>Given that,</em>

<em>The distance = 50mm</em>

<em>The time t =10 seconds</em>

<em>The force F = 10kN</em>

<em>The piston diameter is = 100mm</em>

<em>The pressure = F/A</em>

<em> 10 * 10^3/Δ/Δ </em>

<em> P = 1273885.3503 pa</em>

<em>Then</em>

<em>Power = work/time  = Force * distance /time</em>

<em> = 10 * 1000 * 0.050/10</em>

<em>which is  =50 watt</em>

<em>Power =∅ΔP</em>

<em>50 = 1273885.3 ∅</em>

5 0
3 years ago
A consolidation test was performed on a sample of fine-grained soil sample taken from a depth such that the vertical effective s
Scorpion4ik [409]

Answer:

The settlement that is expected is 1.043 meters.

Explanation:

Since the pre-consolidation stress of the layer is equal to the effective stress hence we conclude that the soil is normally consolidated soil

The settlement due to increase in the effective stress of a normally consolidated soil mass is given by the formula

\Delta H=\frac{H_oC_c}{1+e_o}log(\frac{\bar{\sigma_o}+\Delta \bar{\sigma }}{\bar{\sigma_o}})

where

'H' is the initial depth of the layer

C_c is the Compression index

e_o is the inital void ratio

\bar{\sigma_o} is the initial effective stress at the depth

\Delta \bar{\sigma_o} is the change in the effective stress at the given depth

Applying the given values we get

\Delta H=\frac{8\times 0.3}{1+0.87}log(\frac{154+28}{154})=1.04

3 0
3 years ago
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