Explanation:
Thermodynamics system :
Thermodynamics system is a region or space in which study of matters can be done.The system is separated from surroundings by a boundary this boundary maybe flexible or fixed it depends on situations.The out side the system is called surroundings.
Generally thermodynamics systems are of three types
1.Closed system(control mass system)
Only energy transfer take place ,no mass transfer take place.
2.Open system(control volume system)
Both mass as well as energy transfer take place.
3.Isolated system
Neither mass or nor energy transfer take place.
At steady state ,property is did not changes with respect to time.
Answer:
a) Fb= 275.77 lb Fc= 142.75 lb
b) M = -779.97 lb.ft (i.e. 779.97 lb.ft in clockwise direction)
c) Fax = 195 lb
Fay = 337.75 lb
Fbx = 195 lb
Fby = 195 lb
Explanation:
Question: Three tugboats are used to turn a barge in a narrow channel. To avoid producing any net translation of the barge, the forces applied should be couples. The tugboat at point A applies a 390 lb force.
(a) Determine FB and FC so that only couples are applied.
(b) Using your answers to Part (a), determine the resultant couple moment that is produced.
(c) Resolve the forces at A and B into x and y components, and identify the pairs of forces that constitute couples.
Solution:
<u>For this problem Right hand side is positive X direction and Upwards is positive Y direction. Couples and moments will be considered positive in counterclockwise direction.</u>
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a) For no translation condition
∑
& ∑
Hence,


and

Inserting the value of
and solving the remaining equations simultaneously yields (magnitudes),
b) Summing up moments

(i.e. 779.97 lb.ft clockwise)
c)



Answer:
6.65 kPa.
- 73.3 kPa.
Explanation:
Without much ado let's jump right into the solution to the problem given. It is given that the pressure = 50 mmHg and the solution to this question is to write out the value of the pressure in kpa and kPa gauge.
P(a) = 0.05m × 133 kN/m³ = 6.65 kPa.
The P(gauge) =( [ 0.05 × 13.6 × 9810] ÷ 1000 ) - 80 = - 73.3 kPa.
Answer:
Reverse engineering
Explanation:
Reverse Engineering is the remaking of already made products following the deconstruction and examination of the product to make known the product design, code and architecture features, gain knowledge of the composition and construction in a scientific research approach
Reverse engineering is also known as back engineering and consists of three main stages
1) Recovery implementation
2) Design recovery
3) Recovery analysis.