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Cerrena [4.2K]
3 years ago
14

Calculate the magnitude and direction (i.e., the angle with respect to the positive H-axis, measured positive as counter-clockwi

se) of the total force acting on M. Notice that the arrows representing the forces end on grid intersections.

Chemistry
1 answer:
r-ruslan [8.4K]3 years ago
4 0

The graphics in the attachment is part of the question, which was incomplete.

Answer: Fr = 102N and angle of approximately 11°.

Explanation: From the attachment, it is observed that from the three forces acting on M, two are perpendicular. So to find them, we have to show their x- and y- axis components. From the graph:

Fx = 70+40-10 = 100

Fy = 40-20 = 20

Now, as the forces form a triangle, the totalforce is:

Fr = \sqrt{Fx^{2} +Fy^{2} }

Fr = \sqrt{10400}

Fr = ≈ 102N

To determine the angle requested, we use:

arctg H = \frac{Fy}{Fx}

arctg H = \frac{20}{100}

H = tg 0.2 ≈ 11°.

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