Answer:
321.6 g/Mol
Explanation:
mass of solvent in kilograms = 90g/1000 = 0.09 Kg
Given that;
ΔTf = Kf . m . i
Where;
Kf = freezing point constant = 4.25 °C/Kg mol
m = molality of the solution
i = Van't Hoff factor = 1 (since the substance is molecular)
ΔTf = freezing point of pure solvent - freezing point of solution
freezing point of pure solvent = 3 °C
ΔTf = 3 °C - 2.1 °C
ΔTf = 0.9 °C
0.9= 4.25 * 6.13/M/0.09 * 1
0.9= 26.0525/M * 1/0.09
0.9 = 26.0525/0.09 M
0.9 * 0.09M = 26.0525
M = 26.0525/0.9 * 0.09
M= 321.6 g/Mol
Answer:
10 atm
Explanation:
There's a lot to do here, but lets take it one step at a time. First, let's write a balanced equation for the decomposition of potassium chlorate into potassium chloride and oxgyen gas.
2 KClO3 → 2 KCl + 3 O2
Now let's find the moles of the KClO3 (molar mass 122.55 g/mol) that we have take 10 g/122.55 g/mol, grams will cancel and we are left with 0.0816 moles. lets divide that by two since we have a two in front of the KClO3 in the equation, and then multiply that number by 5 since it's the total moles of products, in summary, multiply by 5/2 to get 0.204 moles.
Now that we know the moles of our products, let's plug some stuff into the ideal gas law PV = nRT. We are looking for P so let's solve for that. P = (nRT)/V, now let's plug in our values. Make sure V is converted to liters so 0.5 L. And convert celcius to kelvin by adding 273
P = ((0.204 moles)(318 K)(0.08206 L atm mol^-1 K^-1))/0.5 L
A lot of units cancel, and we get about 10.65 atm, if you don't want the answer in atm, you can find a conversion equation. But let's round to sig figs for now, which will bring us to 10 atm.
Answer : The volume for 6.0m HCl solution required = 62.5 ml
Solution : Given,
Initial concentration of HCl solution = 6.0m
Final concentration of HCl solution = 1.5m
Final volume of HCl solution = 250 ml
Initial volume of HCl solution = ?
Formula used for dilution is,
where,
= initial concentration
= final concentration
= initial volume
= final volume
Now put all the given values in above formula, we get the initial volume of HCl solution.
= 62.5 ml
Therefore, the volume for 6.0m HCl solution required = 62.5 ml
Im confused here. Add the rest of the question for me to help you
Burning splint test
2H2 (g) + O2 (g) -> 2H20 (g) + heat
It’s a combustion reaction
