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MaRussiya [10]
3 years ago
5

A balloon of helium was put in the freezer at -23°C. Its volume at this temperature was 2.5 liters. It was removed from the free

zer. Eventually, it reached a temperature of 177°C. What would its volume be at this temperature? (Neglect any force used to stretch the rubber balloon.) (1.)45000 (2.) 0.22 (3.) 4.5 (4.) 1.4
Chemistry
1 answer:
kotegsom [21]3 years ago
3 0

4.5 L

Explanation:

We will use the combined gas law formula;

P₁V₁/T₁ = P₂V₂/T₂

Because the pressure remains the same, it cancels out and what remains is;

V₁/T₁ = V₂/T₂

Before evaluating remember to change the temperatures into Kelvin;

-23° = 250.15 K

177° = 450.15 K

We replace the variables with known values;

2.5 / 250.15 = V₂ / 450.15

V₂ = 2.5 /250.15 * 450.15

V₂ = 4.4988 L

≅ 4.5 L

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