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polet [3.4K]
2 years ago
5

Which describes the molecule below?

Chemistry
1 answer:
BartSMP [9]2 years ago
4 0
Picture is too dark cant help
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I will mark brainliest
Veronika [31]

I believe the answer is B??????????? Hope this helps

~Queensupreme

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3 years ago
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Molarity formula what is the molarity of a solution in which 3 moles of nacl is dissolved in 1.5 kg of water
Igoryamba
Molarity is..
1.5 kg H₂O = 1.5L H₂O
So...
\frac{moles}{volume} = molarity
\frac{3.0 mol}{1.5L} = molarity
2M = molarity
7 0
3 years ago
Several billion years ago, which gas was the least prevalent in the atmosphere?
Amiraneli [1.4K]
The least prevalent gas in the atmosphere was oxygen several billion years ago. This is because it was only around 2.4-3 billion years ago when the first photosynthetic bacteria evolved, meaning they produce food from inorganic compounds such as carbon dioxide and water to produce glucose and oxygen. Oxygen is then released in the atmosphere and this is called <em>The Great Oxygenation Event</em>. 
7 0
3 years ago
A fixed mass of oxygen gas occupies 300cm cube at 0 degree centigrade. what volume would the gas occupy at 15 degree centigrade​
egoroff_w [7]

Answer:

Volume occupied by oxygen gas at 15 degree centigrade​ is equal to 316.5 centimeter cube

Explanation:

Assuming Pressure is constant.

\frac{V_1}{T_1} = \frac{V_2}{T_2}

where T1 and T2 are temperature in Kelvin

Substituting the give values we get-

\frac{300}{273} = \frac{V_2}{288}

V_2 = \frac{288*300}{273} \\V_2 = 316.5

Volume occupied by oxygen gas at 15 degree centigrade​ is equal to 316.5 centimeter cube

5 0
2 years ago
Water has a specific heat of 4.18 J/g°C. If 35.0 g of water at 98.8°C loses 4.94 kJ of
stira [4]

Answer:

65°C

Explanation:

Formula for calorimetry is:

Q = C . m . ΔT

Where Q is heat, C is specific heat, m is mass and ΔT is the difference between final T° and initial.

We have all data to replace.

First of all, we convert kJ to J → 4.94 kJ . 1000 J / 1 kJ = 4940 Joules

We made this conversion because the unit of C, is in J

As heat is lost, we have to think in a negative value. Let's replace:

- 4940 J = 4.18 J/ g °C . 35 g . ( Final T° - 98.8°C)

- 4940 J / (4.18 J/ g °C . 35 g) =  Final T° - 98.8°C

Final T° = - 4940 J / (4.18 J/ g °C . 35 g) + 98.8°C

Final T° = 65.03 °C

Notice, that this answer has sense because as T° decreased, heat has been lost.

3 0
3 years ago
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