Answer:
The correct answer is B the tertiary halides reacts faster than primary halides.
Explanation:
During SN2 reaction the nucleophile attack the alkyl halide from the opposite side resulting in the formation of transition state in which a bond is not completely broken or a new bond is not completely formed.
After a certain period of time the nucleophile attach with the substrate by substituting the existing nuclophile.
An increase in the bulkiness in the alkyl halide the SN2 reaction rate of that alkyl halide decreases.This phenomenon is called steric hindrance.
So from that point of view the that statement tertiary halides reacts faster that secondary halide is not correct.
Answer:
the percent error expected from each of theses person's body:
in homes:
% E = 0.14267 %
in doctor's office:
% E = 0.257 %
Explanation:
- ° C = ( ° F - 32 ) * (5/9)
- % E = ( | true - exp | / true ) * 100
- body temp = 38.9 ° C = 102.02 ° F
thermometer used in homes:
⇒ T = 102.02 ° F +/- 0.1 ° F = 102.12 ° F ∧ 101,92 ° F
⇒ T = 102.12 ° F = 38.9555 ° C
⇒ % E = ( | 38.9 - 38.9555 | ) / 38.9 ) * 100 = 0.14267 %
in the doctor's oficce:
⇒ T = 38.9 ° C +/- 0.1 ° C = 39 ° C ∧ 38.8 ° C
⇒ % E = (( | 39 - 38.9 | ) / 38.9 ) * 100 = 0.257 %
There are several information's already given in the question. Based on those information's, the answer can be easily deduced.
Gas constant = 0.0821
Now
<span>PV=nRT
</span>(1.2) * (0.09) = n * (0.0821) * (297)
n = 0.00443
Mass of Butane = 32.105 - 31. 844
= 0.261
Then
Molar mass of Butane gas = 0.261/.00443
= 58.92
Answer:
the mass of the sugar would stay the same i think.
Explanation:
