The first has no r , only 0 since it is a straight line.
Answer:
1) 16
2a) 100 -a -2b
2bi) (100 -a -2b)/4
2bii) 11
Step-by-step explanation:
1. Put the numbers where the corresponding variables are and do the arithmetic.
(2(1) +3(-2))^2 = (2 -6)^2 = (-4)^2 = 16
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2. The pieces cut from the wire have the lengths a, b, b. The sum of those lengths is a+b+b = a+2b.
2a. The remaining length is what is left when the total of cut pieces is subtracted from the original amount:
100 -(a+2b) = 100 -a -2b
2bi. The perimeter of the square is the amount in part (2a). A square has 4 sides of the same length, so each side has a length that is 1/4 of the perimeter. The side length is ...
(100 -a -2b)/4 . . . . length of one side of the square
2bii. Fill in the given values for "a" and "b" and do the arithmetic.
(100 -24 -2(16))/4 = (76 -32)/4 = 44/4 = 11 . . . one side of the square
The size of angle PRQ is 15°
Step-by-step explanation:
In any regular polygon of n-sided
- All sides are equal in length
- All angles are equal in measure
- The measure of each interior angle is

- The measure of each exterior angle is

- The sum of the measures of the interior and exterior angle at the same vertex is 180°
∵ PQ and QR are two sides of a regular 12-sided polygon
∴ PQ = QR
∵ PR is a diagonal
∴ ∠PQR is an interior angle of the polygon
- By using the rule of the interior angle above
∵ n = 12
∴ m∠PQR = 
∴ m∠PQR = 150°
In Δ PQR
∵ PQ = QR ⇒ sides in a regular polygon
- Δ PQR is an isosceles Δ
∴ m∠PRQ = m∠RPQ ⇒ base angles of an isosceles Δ
The sum of the measures of the interior angles of a triangle is 180°
∵ m∠PQR + m∠PRQ + m∠RPQ = 180°
∴ 150 + m∠PRQ + m∠RPQ = 180°
- Subtract 150 from both sides
∴ m∠PRQ + m∠RPQ = 30
∵ m∠PRQ = m∠RPQ
- Divide their sum by 2 to find the measure of each one
∴ m∠PRQ = m∠RPQ = 30 ÷ 2 = 15°
∴ m∠PRQ = 15°
The size of angle PRQ is 15°
Learn more:
You can learn more about the triangles in brainly.com/question/3945600
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Answer:
Step-by-step explanation:
y=12x−2. parallel lines have the same slope 12
find b at point (3,-2)
y=12x+b
-2=12(3)+b
-2-36=b
b=-36
the equation has to be y=12x-38
when you input the point(3,-2)
-2=12(3)-38
-2=-2 correct
<u>Set up the composite function and simplify. </u>
f = 2x + 3,
g = -x^2 + 5,
f(x) o g(x):
D. 134