A Polynomial Identity is True when you work the problem out and both sides are equal to each other

PLEASE HELP!!! What is the slope parallel to 5x + y = 3, please show me step by step, will give the brainliest for this answer.

Andreas93 [3]

Answer:

-5

Step-by-step explanation:

First, put the equation into the form y = mx +b (where m is the slope and b is the y-intercept)

This would look like:

$5x + y = 3\\y = -5x + 3$

This means the slope is -5.

Parallel lines always have the same slope, so the slope of the parallel line is also -5

3 0

3 years ago

A pair of ordinary dice is rolled. What is the probability that each die will show a number higher than 4. 1. (1/36) 2. (1/12) 3

mihalych1998 [28]

Answer:

the answer is 1/12

Step-by-step explanation:

it is 1/12 because if there are only a pair you would have 2 dice. and since each die has numbers all the way up to 6 all you have to do is add them. and don't count all the numbers. like add 1+2+3+4+5+6. that's just plain wrong just do add the highest number on each die (6+6)

8 0

3 years ago

HELP ASAP!!!!!!!!PLEASE<br><br> Solve for x. Please explain. Thank you

Stella [2.4K]

The values are $x=8$ and $y=10$

Explanation:

From the figure, we can see that the two quadrilaterals are similar.

Thus, by the property of quadrilateral, for similar quadrilaterals, their corresponding angles and sides are congruent. Thus, we have,

∠D = ∠S, ∠E = ∠P, ∠G = ∠R and ∠F = ∠Q

Also, GF = QR and DE = PS

Where QR = $2x-4$ and ∠D = 102°, ∠G = 84° and ∠F = 68°, ∠Q = $(6y+x)$ °

Hence, to determine the value of x for the side QR, we have,

Equating the values in GF = QR,we get,

$12=2x-4\\16=2x\\8=x$

Thus, the value of x is 8.

Substituting x in the angle Q to determine the value of y.

Thus, we have,

∠F = ∠Q

$68=6y+x\\68=6y+8\\60=6y\\10=y$

Thus, the value of y is 10.

Hence, The values are $x=8$ and $y=10$

8 0

3 years ago

does the following system of equations have a solution if so find it. 2x+y+z= 4 x-y+3z= -2 -x+y+z= -2

saul85 [17]

I'd suggest using "elimination by addition and subtraction" here, altho' there are other approaches (such as matrices, substitution, etc.).

Note that if you add the 3rd equation to the second, the x terms cancel out, and you are left with the system

- y + 3z = -2
y + z = -2
-----------------
4z = -4, so z = -1.

Next, multiply the 3rd equation by 2: You'll get -2x + 2y + 2z = -2.

Add this result to the first equation. The 2x terms will cancel, leaving you with the system

2y + 2z = -2
y + z = 4

This would be a good time to subst. -1 for z. We then get:

-2y - 2 = -2. Then y must be 0. y = 0.

Now subst. -1 for z and 0 for y in any of the original equations.

For example, x - (-1) + 3(0) = -2, so x + 1 = -2, or x = -3.

Then a tentative solution is (-3, -1, 0).

It's very important that you ensure that this satisfies all 3 of the originale quations.

5 0

4 years ago

I'm really stuck on this:/

JulsSmile [24]

Answer:

9.2

Step-by-step explanation:

put the 4 in for the c. it becomes 16. then subtract

8 0

3 years ago

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