14x - 129 (I think I’m so sorry if it’s wrong)
x=2 is only solution while x=1 is extraneous solution
Option C is correct.
Step-by-step explanation:
We need to solve the equation
and find values of x.
Solving:
Find the LCM of denominators x-1,x and x-1. The LCM is x(x-1)
Multiply the entire equation with x(x-1)

Now, factoring the term:

The values of x are x=1 and x=2
Checking for extraneous roots:
Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.
If we put x=1 in the equation,
the denominator becomes zero i.e
which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.
If we put x=2 in the equation,


So, x=2 is only solution while x=1 is extraneous solution
Option C is correct.
Keywords: Solving Equations and checking extraneous solution
Learn more about Solving Equations and checking extraneous solution at:
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the answer is 59/24 or 2.4583 or 2 11/24
hope it helps
Answer: She would have to burn between 220 and 240 calories per minute to have a calorie burn rate between those of Martin and Paul.
Step-by-step explanation:
Martin:
360 calories / 30 min = 12 calories/min
Paul:
165 calories / 15 min = 11 calories/min
Kara:
Needs to burn between 11 and 12 calories/min, so we'll calculate the range:
11 calories/min x 20 min = 220 calories (minimum # calories she can burn)
12 calories/min x 20 min = 240 calories (maximum # calories she can burn)
Answer:
Algebra
Topics
How do you find the intercepts of x2y−x2+4y=0?
Algebra Graphs of Linear Equations and Functions Intercepts by Substitution
2 Answers
Gió
Mar 24, 2015
For the intercepts you set alternately x=0 and y=0 in your function:
and graphically:
Answer link
Alan P.
Mar 24, 2015
On the X-axis y=0
So
x2y−x2+4y=0
becomes
x2(0)−x2+4(0)=0
→−x2=0
→x=0
On the Y-axis x=0
and the original equation
x2y−x2+4y=0
becomes
(0)2y−(0)2+4y=0
→y=0
The only intercept for the given equation occurs at (0,0)
Answer link
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