The type of polynomial that would best model the data is a <em>cubic</em> polynomial. (Correct choice: D)
<h3>What kind of polynomial does fit best to a set of points?</h3>
In this question we must find a kind of polynomial whose form offers the <em>best</em> approximation to the <em>point</em> set, that is, the least polynomial whose mean square error is reasonable.
In a graphing tool we notice that the <em>least</em> polynomial must be a <em>cubic</em> polynomial, as there is no enough symmetry between (10, 9.37) and (14, 8.79), and the points (6, 3.88), (8, 6.48) and (10, 9.37) exhibits a <em>pseudo-linear</em> behavior.
The type of polynomial that would best model the data is a <em>cubic</em> polynomial. (Correct choice: D)
To learn more on cubic polynomials: brainly.com/question/21691794
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HA + bA = 2
A(h+b) = 2
A = 2/h+b
- 3x + 4y = - 11
y = 2x - 4
-3x + 4(2x - 4) = -11
-3x + 8x - 16 = - 11
5x = -11 + 16
5x = 5
x = 5/5
x = 1
y = 2x - 4
y = 2(1) - 4
y = 2 - 4
y = -2
Solution: (1, -2)
Answer:

Step-by-step explanation:
<u>Roots of a polynomial</u>
If we know the roots of a polynomial, say x1,x2,x3,...,xn, we can construct the polynomial using the formula

Where a is an arbitrary constant.
We know three of the roots of the degree-5 polynomial are:

We can complete the two remaining roots by knowing the complex roots in a polynomial with real coefficients, always come paired with their conjugates. This means that the fourth and fifth roots are:

Let's build up the polynomial, assuming a=1:

Since:


Operating the last two factors:

Operating, we have the required polynomial:
