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Wittaler [7]
2 years ago
6

A 25 foot rope was cut into 2 pieces with the length being a ratio of 5 to 12.

Mathematics
1 answer:
gizmo_the_mogwai [7]2 years ago
8 0

Answer: The short piece is approximately 7.5 feet

Step-by-step explanation: Since the 25 foot rope was cut into 2 pieces and the ratio is 5 to 12, that means the total amount would be 17. 25/17 rounded to the nearest tenths is 1.5. We then multiply 5 by 1.5 because 1.5 is the unit resulting in 7.5. This shows that the shorter piece is approximately 7.5 feet. Hope this helps

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The heights of American men aged 18 to 24 are approximately normally distributed with mean 68 inches and standard deviation 2.5
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Answer:

78.81

Step-by-step explanation:

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PLS HELP!!!! Pointtssss!! The temperature during a very cold day is
grin007 [14]

The type of polynomial that would best model the data is a <em>cubic</em> polynomial. (Correct choice: D)

<h3>What kind of polynomial does fit best to a set of points?</h3>

In this question we must find a kind of polynomial whose form offers the <em>best</em> approximation to the <em>point</em> set, that is, the least polynomial whose mean square error is reasonable.

In a graphing tool we notice that the <em>least</em> polynomial must be a <em>cubic</em> polynomial, as there is no enough symmetry between (10, 9.37) and (14, 8.79), and the points (6, 3.88), (8, 6.48) and (10, 9.37) exhibits a <em>pseudo-linear</em> behavior.

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6 0
2 years ago
HA=2-bA , solve the equation for A
yaroslaw [1]
HA + bA = 2
A(h+b) = 2
A = 2/h+b
7 0
2 years ago
Read 2 more answers
Can someone please help me with this .
schepotkina [342]
- 3x + 4y = - 11
y = 2x - 4

-3x + 4(2x - 4) = -11
-3x + 8x - 16 = - 11
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8 0
3 years ago
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Write a polynomial of degree 5 with zero x=0,i square root 7, -2i
professor190 [17]

Answer:

P(x)=x^5+11x^3+28x

Step-by-step explanation:

<u>Roots of a polynomial</u>

If we know the roots of a polynomial, say x1,x2,x3,...,xn, we can construct the polynomial using the formula

P(x)=a(x-x_1)(x-x_2)(x-x_3)...(x-x_n)

Where a is an arbitrary constant.

We know three of the roots of the degree-5 polynomial are:

x_1=0;\ x_2=\sqrt{7}\boldsymbol{i}:\ x_3=-2\boldsymbol{i}

We can complete the two remaining roots by knowing the complex roots in a polynomial with real coefficients, always come paired with their conjugates. This means that the fourth and fifth roots are:

x_4=-\sqrt{7}\boldsymbol{i}:\ x_3=+2\boldsymbol{i}

Let's build up the polynomial, assuming a=1:

P(x)=(x-0)(x-\sqrt{7}\boldsymbol{i})(x+\sqrt{7}\boldsymbol{i})(x-2\boldsymbol{i})(x+2\boldsymbol{i})

Since:

(a+b\boldsymbol{i})\cdot (a-b\boldsymbol{i})=a^2+b^2

P(x)=(x)(x^2+7)(x^2+4)

Operating the last two factors:

P(x)=(x)(x^4+11x^2+28)

Operating, we have the required polynomial:

\boxed{P(x)=x^5+11x^3+28x}

7 0
3 years ago
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